Answer:
(a) Charge density σ=6.6375×10²nC/m²
(b) Total charge Q=1.47×10²nC
Explanation:
Given Data
A=47.0 cm =0.47 m
Electric field E=75.0 kN/C
To find
(a) Charge density σ
(b)Total Charge Q
Solution
For (a) charge density σ
From Gauss Law we know that
Φ=Q/ε₀.......eq(i)
Where
Φ is electric flux
Q is charge
ε₀ is permittivity of space
And from the definition of flux
Φ = EA
The flux is electric field passing perpendicularly through the surface
Put the this Φ in equation(i)
EA
=Q/ε₀
where Q(charge)=σA
EA=(σA)/ε₀
E=σ/ε₀
σ=ε₀E
σ=6.6375×10²nC/m²
For (b) total charge Q
Q=σA
Answer:
Ф = 142.674 degree
Ф = 2.490131057 rad
wavelength = 0.396316 λ
Explanation:
Given data
combined wave having an amplitude 0.64 times
to find out
answer in degrees, radians, and fraction of the wavelength
solution
let us consider these two wave equation
Asin(ωt) and the Asin (ωt + Ф)
and here Ф is phase difference
so we say
resultant wave is
Y = Asin(ωt) + Asin (ωt + Ф) = Asin(ωt + Ф/2) cos ( Ф/2)
so Y = A' sin(ωt + Ф/2)
we know that here resultant wave amplitude is 2A cos ( Ф/2)
so
put A= 0.64 A
so 2Acos ( Ф/2) = 0.64 A
and Ф/2 = 71.3370
Ф = 142.674 degree
Ф = 2.490131057 rad
so wavelength is 2.490131057 / 2π
wavelength = 0.396316 λ
Answer:
<em>The object takes 3.84 seconds to return to earth.</em>
Explanation:
<u>Projectile Motion</u>
It's when an object projected above the ground at a certain velocity, moves along a curved path under the action of gravity.
The initial velocity has two components, given by:
Where vox is the initial component of the velocity in the horizontal direction, voy is the initial component of the velocity in the vertical direction, and t is the time.
The object reaches a maximum height and then it returns to the ground. The time it takes to reach the maximum height can be calculated when the vertical component of the velocity is zero:
The initial vertical component of the velocity is 18.8 m/s, thus:
The total time is double that time:
The object takes 3.84 seconds to return to earth.
Answer:
Explanation:
First ship starts at Noon with speed 20 Knots towards West
now we know that 2nd ship starts at 6 PM with speed 15 Knots towards North West
so after time "t" of 2nd ship motion the two ships positions are given as
now we can find the distance between two ships as
now we have
now we will differentiate it with respect to time
here we know that
so we have
now we have
Answer:
Explanation:
PE = mgh = 2.0(9.8)(1.2) = 23.52 ≈ 24 J
Translation kinetic energy is defined as the energy of a system due to the motion of the system’s...center of mass
KE = ½mv² = ½(45)(1800/600)² = 202.5 ≈ 203 J
