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gayaneshka [121]
3 years ago
6

A simple cyanine dye molecule has a long central carbon chain, with a total of 8 bonds, between the two nitrogen atoms. One elec

tron per bond is essentially free to move up and down this chain. The potential energy for such an electron can be modeled as a one-dimensional box. The distance between each bond is about 0.14 nm.
What would be the transition corresponding to the lowest energy photon that this molecule could absorb? Would such a photon be in the visible range?
Physics
1 answer:
wariber [46]3 years ago
4 0

Answer:

For one dimensional box

E= n^{2}h^{2}/ 8mL^{2}

For lowest energy transition will be from n =1 to n=2

Hence,

hc/\lambda = 2^{2}h^{2}/ 8mL^{2} - h^{2}/8mL^{2}

h= 6.626 *10-34 J.s

m = 9.31 *10-31 Kg

L= 0.14 * 10-9 m

c= 3 *108 m/s

\lambda = 8*c*m*L^{2} / 3*h

\lambda = 22 nm

Not in visible range

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I would kick this question back to the Physics teacher.  It's meaningless,
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Explanation:

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Explanation:

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From the question,

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