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3 years ago

PLEASE ILL GIVE BRAINLIST Which term describes the high point of a transverse wave?

Physics

1 answer:

Pani-rosa [81]3 years ago

6 0

Answer:

I belive that the answer is the A

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In a physics lab, a 0.500-kg cart (Cart A) moving with a speed of 129 cm/s encounters a magnetic collision with a 1.50-kg cart (

omeli [17]

Answer:

58 cm/s

Explanation:

0.5×129=0.5×(-45)+1.5×V

V=58

7 0

3 years ago

How much work must be done to stop a 1100-kg car traveling at 112 km/h?(Hint: You will need to convert the speed first.)Answer:

zimovet [89]

According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

$W=\Delta K$

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

$K=\frac{1}{2}mv^2$

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

$\begin{gathered} K=\frac{1}{2}(1100kg)\left(112\frac{km}{h}\times\frac{1\frac{m}{s}}{3.6\frac{km}{h}}\right)^2=532,345.679...J \\ \\ \therefore K\approx532,346J \end{gathered}$

Therefore, the answer is: 532,346 J.

5 0

1 year ago

If the ball hits olaf and bounces off his chest horizontally at 8.50 m/s in the opposite direction, what is his speed vf after t

Feliz [49]

Answer:

16s/m

Explanation:

3 0

4 years ago

What experiment should I make using Gravitational Force? <br><br>PLEASE HELP ME :)

Bogdan [553]

You could try the "Spinning Bucket" or the "Center Of Gravity" experiment. There are plenty more that you could research! Hope this helped :)

8 0

3 years ago

If you drive 30 miles in 40 minutes, and then 15 miles in 20 minutes, do you have a constant speed?

kompoz [17]

Answer:

A) yes

Explanation:

First section of trip: 30 miles in 40 minutes

Second section of trip: 15 miles in 20 minutes

The formula for speed is distance over time $k=\frac{d}{t}$

Calculate the speeds for each section of the trip.

First:

k = d/t

k = 30miles/40minutes <= reduce fraction by 10 (30÷10 and 40÷10)

k = 3 miles / 4 minutes

Second:

k = d/t

k = 15miles/20minutes <= reduce fraction by 5 (15÷5 and 20÷5)

k = 3 miles / 4 minutes

Therefore there is a constant speed because both sections of the trip are driving at "3 miles / 4 minutes".

3 miles / 4 minutes can be also formatted as:

0.75 miles per minute.

7 0

3 years ago