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AysviL [449]
3 years ago
5

When pumping air into a tire, you have to pull back on the pump plunger to fill the pump with air. This increases the volume of

the air inside the pump. This increase in volume has what effect on the gases inside the pump?
Question 9 options:

the gas molecules inside the pump are able to spread out more which decreases the pressure of the gas.


the gas molecules inside the pump get compressed and packed closer together which decreases the pressure of the gas.


the gas molecules inside the pump are able to spread out more which increases the pressure of the gas.


the gas molecules inside the pump get compressed and packed closer together which increases the pressure of the gas.
Chemistry
2 answers:
Monica [59]3 years ago
5 0
6969696969 there hope
Levart [38]3 years ago
4 0

Answer:

Pulling back on the plunger allows you to put in more air into the pump and the more air you have inside a fixed volume, the greater the pressure becomes. (D)

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Vapor obtained by evaporating 0.495 grams of an unknown liquid is collected in a 127 mL flask. At 371 K, the pressure of the vap
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Answer:

The molar mass in g/mol is 121.4 g/m

Explanation:

Let's apply the Ideal Gases Law to solve this:

P . V = n . R. T

V = 125 mL → 0.125L

P = 754 Torr

760 Torr ___ 1 atm

754 Torr ____ (754 / 760) = 0.992 atm

Moles = Mass / Molar mass

0.992 atm . 0.125L = (0.495 g / MM) . 0.082 . 371K

(0.992 atm . 0.125L) / (0.082 . 371K) = (0.495 g / MM)

4.07x10⁻³ mol = 0.495 g / MM

MM = 0.495 g / 4.07x10⁻³ mol → 121.4 g/m

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What is the ph of an aqueous solution with the hydronium ion concentration : [h3o+] = 3 x 10-5 m ?
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[H+ ] = 3 * 10-5 M

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pH = - log [H+ ]

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In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq)
lyudmila [28]

Answer : The mass of NaBr is, 295.323 grams

Solution :

First we have to calculate the moles of NaNO_3.

\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=\frac{244g}{85g/mole}=2.87moles

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaNO_3 react with 2 moles of NaBr

So, 2.87 moles of NaNO_3 react with 2.87 moles of NaBr

Now we have to calculate the mass of NaBr.

\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr

\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g

Therefore, the mass mass of NaBr is, 295.323 grams

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