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AysviL [449]
3 years ago
5

When pumping air into a tire, you have to pull back on the pump plunger to fill the pump with air. This increases the volume of

the air inside the pump. This increase in volume has what effect on the gases inside the pump?
Question 9 options:

the gas molecules inside the pump are able to spread out more which decreases the pressure of the gas.


the gas molecules inside the pump get compressed and packed closer together which decreases the pressure of the gas.


the gas molecules inside the pump are able to spread out more which increases the pressure of the gas.


the gas molecules inside the pump get compressed and packed closer together which increases the pressure of the gas.
Chemistry
2 answers:
Monica [59]3 years ago
5 0
6969696969 there hope
Levart [38]3 years ago
4 0

Answer:

Pulling back on the plunger allows you to put in more air into the pump and the more air you have inside a fixed volume, the greater the pressure becomes. (D)

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Answer:

13.5 %

Explanation:

First we<u> calculate the mass of 500 mL of water</u>, using <em>its density</em>:

  • Volume * Density = Mass
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Then we <u>calculate the mass percent of potassium sulfate</u>, using the formula:

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6 0
2 years ago
Look at the following equation.
Ronch [10]

Answer:

A

Explanation:

_N2 + _H2 - _NH3

LHS RHS

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4 0
3 years ago
Be sure to answer all parts. Rubidium and bromine atoms are depicted at right. Answer the following questions. (a) What is the c
finlep [7]

The complete question is found on the image attached.

Answer:

a) Rb= +1, Br= -1

b)Bromide and rubidium ions are related to krypton

c) C

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Rubidium is found in group 1 with a charge of +1. Bromine is found in group 17 with a charge of -1. Both species have the same configuration as krypton. The ionic sizes of the ions are a very similar to each other Rb+ is 166 while Be is 167.

This RbBr is an ionic compound.

6 0
4 years ago
A weather balloon contains 1.10X10 to the power of 5 mol of helium and has a volume of 2.70x10 to the power of 6 L at 1.00 atm p
olchik [2.2K]

Answer:

299.14 K or 26°C

Explanation:

The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas.

The ideal gas law is often written as

PV = nRT

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V= 2.70 x 10^6 L  

P= 1.00 atm= 101.325 kPa  

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when the formula is  rearranged, T=PV/ nR  

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T = 299.1421917 K

or

T = 299.14 - 273.15 = 25.99 =  26°C

4 0
3 years ago
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astraxan [27]

Answer:

The energy profile for rotation about the C-C bond in ethane is shown in the image, along with the Newman projections of the corresponding ethane conformer.

Explanation:

If you see the ethane molecule (second image) from the C-C bond axis (third image), as in the Newman projections, it's easy to draw an angle between one of the hydrogen atoms of the visible carbon, the carbon itself, and one of the hydrogens of the hidden carbon.

When you make a rotation about the C-C bond, the angle between those hydrogens will change. If you start with an eclipsed conformation, with each hydrogen of the hidden C exactly behind the hydrogens of the visible C, the angle will be 0°, or also 120° or 240°, as this rotations will be equivalent. On the other hand, if the angle is 60° (or 180°, or 300°), you will have a staggered conformation. The eclipsed conformation is less stable than the staggered one, because the interactions between hydrogens will be bigger (the repulsion between their electrons), and because of that the eclipsed conformations will be found in the maxima, while the staggered one will be found in the minima.

8 0
3 years ago
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