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Ray Of Light [21]
4 years ago
14

When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room. Which sentence explains t

his?
a) Gases do not have a definite volume.
B)The particles of gases are closely packed.
C)The force of attraction between particles in gases is very high.
D)Gases are not matter.
Physics
2 answers:
monitta4 years ago
7 0
A. 

since they do not have a definite volume, this causes it to spread out in the air 
guajiro [1.7K]4 years ago
5 0

Answer:

Gases do not have definite volume.

Explanation:

Solids, liquids and gas are three forms of matter. Solids have fixed shape and volume. Liquids do not have fixed shape but have fixed volume. Gases neither have fixed shape nor volume. The particles of solid are tightly packed whereas the particles of gas are very loosely packed and the force of attraction between the particles of gas is very weak.

When the perfume bottle is opened, some liquid changes to gas and fragrance spreads around the room because the particles of gas are very loosely packed and the force of attraction between the particles of gas is very weak. The gas particles do not have fixed volume and easily spread.

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Answer:

15.0 N

Explanation:

see pic

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3 years ago
It uses a series of filters to decompose the multiplexed signals into its constituent component signals. a. Demodulator b. Demul
harkovskaia [24]

Answer:

b) Demultiplexer.

Explanation:

The multiplexed signal occupies the total bandwidth of the communications channel, while that the constituent component signals, occupy only a small part of the bandwidth.

Prior to be demodulated, they must be separated each other, which is done (in a FDM multiplexing scheme) using a series of band-pass filters.

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4 years ago
A spherical, conducting shell of inner radius r1= 10 cm and outer radius r2 = 15 cm carries a total charge Q = 15 μC . What is t
lutik1710 [3]

a) E = 0

b) 3.38\cdot 10^6 N/C

Explanation:

a)

We can solve this problem using Gauss theorem: the electric flux through a Gaussian surface of radius r must be equal to the charge contained by the sphere divided by the vacuum permittivity:

\int EdS=\frac{q}{\epsilon_0}

where

E is the electric field

q is the charge contained by the Gaussian surface

\epsilon_0 is the vacuum permittivity

Here we want to find the electric field at a distance of

r = 12 cm = 0.12 m

Here we are between the inner radius and the outer radius of the shell:

r_1 = 10 cm\\r_2 = 15 cm

However, we notice that the shell is conducting: this means that the charge inside the conductor will distribute over its outer surface.

This means that a Gaussian surface of radius r = 12 cm, which is smaller than the outer radius of the shell, will contain zero net charge:

q = 0

Therefore, the magnitude of the electric field is also zero:

E = 0

b)

Here we want to find the magnitude of the electric field at a distance of

r = 20 cm = 0.20 m

from the centre of the shell.

Outside the outer surface of the shell, the electric field is equivalent to that produced by a single-point charge of same magnitude Q concentrated at the centre of the shell.

Therefore, it is given by:

E=\frac{Q}{4\pi \epsilon_0 r^2}

where in this problem:

Q=15 \mu C = 15\cdot 10^{-6} C is the charge on the shell

r=20 cm = 0.20 m is the distance from the centre of the shell

Substituting, we find:

E=\frac{15\cdot 10^{-6}}{4\pi (8.85\cdot 10^{-12})(0.20)^2}=3.38\cdot 10^6 N/C

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A 30.0-kg packing case is initially at rest on the floor of a1500-kg pickup truck. The coefficient of static friction betweenthe
777dan777 [17]

Answer:

Explanation:

a ) maximum friction possible

= .3 x 30 x 9.8

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Friction force F

F = ma

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It will be in north direction , the direction of acceleration.

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But maximum friction force is 75.3 N , so load will start slipping northward. so friction force will be acting southward.

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5 0
3 years ago
HELP + extra pts // Two 10-m high diving platforms are at opposing ends of a 30-m pool. How fast must two clowns run straight of
ZanzabumX [31]

Explanation:

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We'll assume no force acts on the clowns horizontally to slow them down while they are in flight. And we'll assume that only gravity acts on the clowns vertically.

We can treat the horizontal and vertical components separately. This will help simplify the problem.

Let's start with the vertical displacement. Let's say the clown is dropped from a height of 10-m. How long would it take them to fall that distance?

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Let's solve. 10 = 0*t + \frac{1}{2} (9.8) t^2 \rightarrow 20/9.8 = t^2 \rightarrow t = \sqrt{20/9.8}

Now that we know time, we can calculate how fast the clown needs to be running when they leap from the diving board to cover a distance of 15-m (Remember, half the width of the pool.)

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We assumed no forces act horizontally on the clown, therefore a = 0. We just need to solve for v. Substituting in the time we just solved for, we get something like this. 15 = v \sqrt{20/9.8}

I'll leave it to you to solve this equation.

6 0
3 years ago
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