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3 years ago

Does the surrounding air become warm or cool when vapour phase of h2o condenses?explain.

1 answer:

8 0

When the vapor phase of h20 condenses, the surrounding air becomes a little cold since it liberates some amount of heat energy in order to change its phase from the gaseous state (vapor) to the liquid state (droplets of water).

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This one too dude help me

Mrac [35]

Answer:

Vas happenin!!

atomic number: 5

Atomic mass: 10.81

Number of protons: 5

Number of neutrons: 5

Number of electrons: 5

Hope this helps!

-Zayn Malik

Explanation:

5 0

3 years ago

Putting a marshmallow directly in the fire

Greeley [361]

Answer:

A conduction is the answer

Explanation:

5 0

2 years ago

A stretched string is observed to have four equal segments in a standing wave driven at a frequency of 480 hz. what driving freq

Korvikt [17]

600Hz is the driving frequency needed to create a standing wave with five equal segments.

To find the answer, we have to know about the fundamental frequency.

<h3>How to find the driving frequency?</h3>

The following expression can be used to relate the fundamental frequency to the driving frequency;

f(n) = n * f (1)

where, f(1) denotes the fundamental frequency and the driving frequency f(n).

The standing wave has four equal segments, hence with n=4 and f(n)=4, we may calculate the fundamental frequency.

f(4) = 4× f (1)

480 = 4× f(1)

f(1) = 480/4 =120Hz.

So, 120Hz is the fundamental frequency.

To determine the driving frequency necessary to create a standing wave with five equally spaced peaks?
For, n = 5,

f(n) = n 120Hz,

f(5) = 5×120Hz=600Hz.

Consequently, 600Hz is the driving frequency needed to create a standing wave with five equal segments.

Learn more about the fundamental frequency here:

brainly.com/question/2288944

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8 0

1 year ago

Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n=1. 56) at an angle of 60°. what is the

ankoles [38]

The angle of reflection is "60°".

Here we apply the law of the concept of reflection then we get the final answer easily.

The angle of incident = angle of reflection

Then, the Angle of the incident =60°

What is reflection?

Reflection is the phenomenon of light rays returning to the source after striking an obstruction.
It resembles the way a ball bounces when we toss it on a hard surface.
Some of the light rays that strike an item are reflected, some of them travel through it, and the remainder are absorbed by the object.
The given values are:Light from a monochromatic source,= 560 nm
The angle of incidence,= 60°
The surface of fused quartz (n),= 1.56
When a light ray does exist on a flat surface, the law or idea of reflection should apply since it includes both the reflected and "normal" light rays at the mirror surface.
According to the above law,Angle of incident = angle of reflection
Then, Angle of incident =60°.

To learn more about reflection visit: brainly.com/question/15487308

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7 0

2 years ago

A plastic rod 1.3 m long is rubbed all over with wool, and acquires a charge of -3e-08 coulombs. we choose the center of the rod

Anestetic [448]

(a) The plastic rod has a length of L=1.3m. If we divide by 8, we get the length of each piece:
$L/8=1.3m/8=0.1625 m$

(b) The center of the rod is located at x=0. This means we have 4 pieces of the rod on the negative side of x-axis, and 4 pieces on the positive side. So, starting from x=0 and going towards positive direction, we have: piece 5, piece 6, piece 7 and piece 8. Each piece is 0.1625 m long. Therefore, the center of piece 5 is at 0.1625m/2=0.0812 m. And the center of piece 6 will be shifted by 0.1625m with respect to this:
$c_6 = 0.0812m+0.1625m=0.2437 m$

(c) The total charge is $Q=-3 \cdot 10^{-8}C$ . To get the charge on each piece, we should divide this value by 8, the number of pieces:
$Q/8=-3\cdot 10^{-8}C/8=-3.75\cdot 10^{-9}C$

(d) We have to calculate the electric field at x=0.7 generated by piece 6. The charge on piece 6 is the value calculated at point (c):
$q= -3.75\cdot 10^{-9}C$
If we approximate piece 6 as a single charge, the electric field is given by
$E=k_e \frac{q}{d^2}$
where $k_e=8.99\cdot 10^9Nm^2C^{-2}$ and d is the distance between the charge (center of piece 6, located at 0.2437m) and point a (located at x=0.7m). Therefore we have
$E= 8.99\cdot 10^9 Nm^2C^{-2} \frac{-3.75\cdot 10^9 C}{(0.2437m-0.7m)^2} =-161.9 V/m$
poiting towards the center of piece 6, since the charge is negative.

(e) missing details on this question.

5 0

3 years ago