Answer:
F1= 122.93 N
Explanation:
Pascal´s Principle
Pascal´s Principle can be applied in the hydraulic press:
If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area (A2) of the piston:
P=F/A
P1=P2
Formula (1)
Data
D1 = 1.85 cm : primary cylinder piston diameter
D2 = 24.5 cm : secondary cylinder piston diameter
m = 2200-kg : car mass
Piston area calculation


A1= 2.688 cm²


A2 = 471.435 cm²
Calculating of the weight of the car (W)
W = m*g = 2200-kg * 9.8 m/s² = 21560 N
Calculation of the force in Newtons to be exerted on the primary cylinder piston
Data:
A1= 2.688cm²
A2= 471.435 cm²
F2 = W= 21560 N
We replace data in the formula (1)


F1= 122.93 N
Answer:
go to like the play ground area, and start off by practicing kicking the ball and getting the buttons on the controller down. watch some yt videos too, they will help out!!
Explanation:
hope this helped :))
Answer:
The period of the resulting oscillatory motion is 0.20 s.
Explanation:
Given that,
Spring constant 
We need to calculate the time period
The object is at rest and has no elastic potential but it does has gravitational potential.
If the object falls then the the gravitational potential change in to the elastic potential.
So,


Where,h = distance
k = spring constant
Put the value into the formula


Using formula of time period

Put the value into the formula


Hence, The period of the resulting oscillatory motion is 0.20 s.
Explanation:
I will do two of each as examples.
Boyle's law says that at constant temperature, the product of the initial pressure and volume equals the product of the final pressure and volume.
1. P₁ V₁ = P₂ V₂
(1.5 atm) (10.0 L) = (0.75 atm) V
V = 20.0 L
2. P₁ V₁ = P₂ V₂
(100.0 kPa) (500.0 mL) = P (1,000.0 mL)
P = 50.0 kPa
Charles' law says that at constant pressure, the quotient of the initial volume and temperature equals the quotient of the final volume and temperature.
6. V₁ / T₁ = V₂ / T₂
(10.0 L) / (1500 K) = V / (750 K)
V = 5.0 L
7. V₁ / T₁ = V₂ / T₂
(500.0 mL) / (100 K) = (1000.0 mL) / T
T = 200 K
A scientist can assess whether a pure niobium sample is responsible for contaminating the lab with radioactivity by testing the sample. By testing the niobium sample, a scientist can determine whether it has any other element.