Answer : 7.87 X
![10^{-6}](https://tex.z-dn.net/?f=%2010%5E%7B-6%7D%20)
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Explanation : To find the fraction of schottky defects in the given lattice of CsCl,
we use the formula,
![\frac{N_{s} }{N}} = exp ( \frac{-Q_{s}}{2KT} )](https://tex.z-dn.net/?f=%20%5Cfrac%7BN_%7Bs%7D%20%7D%7BN%7D%7D%20%3D%20exp%20%28%20%5Cfrac%7B-Q_%7Bs%7D%7D%7B2KT%7D%20%29)
on solving with the given values ,
![Q_{s}= 1.86 eV](https://tex.z-dn.net/?f=Q_%7Bs%7D%3D%201.86%20eV)
and T as 645 + 273 K and rest are the constants.
![\frac{N_{s} }{N}} = exp ( \frac{-1.86 eV}{2 X (8.62 X 10^{-5}) X (645 +273)} )](https://tex.z-dn.net/?f=%5Cfrac%7BN_%7Bs%7D%20%7D%7BN%7D%7D%20%3D%20exp%20%28%20%5Cfrac%7B-1.86%20eV%7D%7B2%20X%20%288.62%20X%2010%5E%7B-5%7D%29%20X%20%28645%20%2B273%29%7D%20%29)
we get the answer as 7.87 X
![10^{-6}](https://tex.z-dn.net/?f=%2010%5E%7B-6%7D%20)
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Answer:
Based on my EXPLAIN i think the answer is C.
Explanation: A chemical reaction is a process that leads to the chemical transformation of one set of chemical substances to another. Classically, chemical reactions encompass changes that only involve the positions of electrons in the forming and breaking of chemical bonds between atoms, with no change to the nuclei (no change to the elements present), and can often be described by a chemical equation. Nuclear chemistry is a sub-discipline of chemistry that involves the chemical reactions of unstable and radioactive elements where both electronic and nuclear changes can occur.
Answer:
3
Explanation:
Lt= Loe^(-kt)
Data:
Lo = 10 mg/mL
Assume k = 0.23/da
1. Calculate L5
L5 = 10e^(-5×0.23) = 10e^-1.15 = 10 × 0.317 = 3.17 mg/mL
2. Calculate the dilution factor
You expect to find L5 to be about 3
You want L5 to be about 1.
You should use a dilute your sample by a factor of 3.
P = 3