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2 years ago

What is the mass of 7.675 x 1023 atoms C? Answer in units of g.

Chemistry

1 answer:

nalin [4]2 years ago

3 0

Answer: 15.3 grams C

Explanation: 1 mole is 6.02x10^23 atoms. We can find the moles of C in 7.675 x 10^23 atoms of C by dividing:

(7.675 x 10^23 atoms C)/(6.02x10^23 atoms C/mole) = 1.275 moles C

The molar mass of carbon is 12g/mole. So the mass of 7.675 x 10^23 atoms is (1.275 moles C)*(12 g/mole C) = 15.3 grams.

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3 years ago

2HgCl2(aq) + C2O42–(aq) → 2Cl–(aq) +2CO2(g) + Hg2Cl2(s)

alexgriva [62]

Explanation:

Expression for rate of the given reaction is as follows.

Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]

Therefore, the reaction equations by putting the given values will be as follows.

$1.8 \times 10^{-5} = k[0.105]x [0.15]y$ ............. (1)

$7.2 \times 10^{-5} = k [0.105]x [0.30]y$ ........... (2)

$3.6 \times 10^{-5} = k [0.0525]x [0.30]y$ ............ (3)

Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3) we get the value of x = 1.

Therefore, expression for rate of the reaction is as follows.

Rate = $k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y$

Rate = $k [HgCl2]1 [C_{2}O^{-2}_{4}]2$

Hence, total order = 1 + 2 = 3

According to equation (1),

$1.8 \times 10^{-5} = k[0.105]x [0.15]y$

$1.8 \times 10^{-5} = k [0.105]1 [0.15]2$

k = $7.6 \times 10^{-3} M^{-2} min^{-1}$

Thus, we can conclude that rate constant for the given reaction is $7.6 \times 10^{-3} M^{-2} min^{-1}$ .

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2 years ago

What is the empirical formula of a compound containing carbon, hydrogen, and oxygen in the ratio 14:42:84?

Alexxandr [17]

<h3>Answer:</h3>

D. CH₃O₆

<h3>Explanation:</h3>

We are given the ratio of carbon, hydrogen and oxygen in a compound as 14: 42 : 84

We are supposed to determine the empirical formula of the compound;

We need to know what is an empirical formula;

An empirical formula of a compound is a formula that shows the simplest whole number ratio of elements in a compound.

In this case;

The ratio of C : H : O is 14 : 42 : 84

Note, this is not the simplest ratio.

But we can simplify further to get the simplest whole number ratio;

Therefore, 14 : 42 : 84 is equal to 1 : 3 : 6

Thus, the simplest whole number ratio of C : H : O in the compound is 1 : 3 : 6

Therefore, the empirical formula of the compound is CH₃O₆

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