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Assoli18 [71]
3 years ago
6

Identify the major force between molecules of pentane. dispersion dipole-dipole hydrogen bonding ion-dipole ion-ion

Chemistry
2 answers:
Alex Ar [27]3 years ago
8 0

Answer:

The correct answer is option A, Dispersion Force

Explanation:

The molecules and atoms of n-pentane are non-polar and thus there is no chance of any dipole –dipole interaction between the molecules of n –pentane. There exists repulsion between the electrons moving in near to each other in respective orbits. The molecule of n-pentane processes instantaneous dipole moment  due to instantaneous distribution of electrons and since the molecules are very close to each other instantaneous dipole moment   in one molecule induces instantaneous dipole moment   in the other molecule and thus there exists an attractive force between the non polar molecules of n –pentane  known as Dispersion Forces

Lyrx [107]3 years ago
5 0
It wouldn’t be hydrogen bonding because hydrogen bonding takes place with highly electronegative elements like N,O & F being the most electronegative. It’s not ion - dipole because there is no ion present. So I’m sure it is dispersion
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Answer:

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Explanation:

  • molarity (M) [=] mol/L

∴ w KIO3 = 553 g

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⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol

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⇒ M KIO3 = 1.254 mol/L

3 0
3 years ago
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Answer:

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3 years ago
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ch4aika [34]
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</span>
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3 years ago
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natulia [17]

Answer:

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Explanation:

I pretty much covered it in my answer!

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8 0
3 years ago
how many mL of a 3.5 M sodium hydroxide will be needed to neutralize 15mL of a 4.3 M hydrochloric acid solution?
kobusy [5.1K]
Step 1 : write a valanced equation..
NaOH + HCl 》NaCl + H2O

Step 2 : find the number of mole of HCl..
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Stem 3 : use mole ratio....
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Step 4 :
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Do the calculation
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3 years ago
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