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Aloiza [94]
3 years ago
12

A group of naturalists catch, tag and release 121 trout into a lake. The next day they catch and release 48 trout, of which 22 h

ad been tagged. Using this ratio, how many trout would be estimated to be in the lake?
Mathematics
2 answers:
RideAnS [48]3 years ago
8 0

Answer:

264.

Step-by-step explanation:

Let x represent the number of trout in the lake.

We have been given that a group of naturalists catch, tag and release 121 trout into a lake. The next day they catch and release 48 trout, of which 22 had been tagged.

Using proportions, we will get:

\frac{\text{Total trouts}}{\text{Tagged trouts}}=\frac{48}{22}

\frac{x}{121}=\frac{48}{22}

\frac{x}{121}*121=\frac{48}{22}*121

x=\frac{24}{11}*121

x=24*11

x=264

Therefore, there would be approximately 264 trout in the lake.

dalvyx [7]3 years ago
8 0

264 trouts are estimated to be in the lake.

Using proportion, we write: Tagged trout/Total Trout

This becomes 22/48.

In order to use cross multiplication, we write another fraction using x, the total number of trout in the lake: 121/x.

Now we have 121/x=22/48.

We cross multiply.

121*48=22x.

(121*48)/22 becomes:

264.

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Answer:

x = -7

Step-by-step explanation:

-6x + 3 = 45

First, we need to get rid of the 3 by subtracting it by 3. We need to do the same to the number on the other side.

-6x + 3 = 45

      -3    -   3

-<em>6x = 42</em>

Then, to iolate the x, we need to divide -6 by itself to cancel the number out and get x alone. We also need to divide 42 by -6 as well.

\frac{-6x}{-6} = \frac{42}{-6}

42 divided by -6 is -7.

x=-7

I hope this helps!

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Step-by-step explanation:

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I dont understand and this is very urgent so can someone help me out please?
wariber [46]

Answer:

Please Find the solution below

Step-by-step explanation:

Let us say the two equations are

x+y=5            --------------(A)

x-y=1              -------------(B)

Let us solve them for x and y by adding them

2x=6

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Hence from (A)

3+y=5

y=2

Hence our solution is

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Adding same number to equation (A) say 2 we get

x+y+2=5+2

x+y=5+2-2

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Hence equation remains the same while adding same number to each side.

Same thing happens if we add same number to equation (B)

Hence we draw the conclusion that the solution remains the same if same number is added to each side of the original equation.

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What is the value of the number 6 in the total number 4560 thousand
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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
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