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Kobotan [32]
3 years ago
7

What metal has 95 protons Lead, mercury, americium, or francium?

Chemistry
1 answer:
UkoKoshka [18]3 years ago
5 0

Americium

Explanation:

The metal with 95 protons is Americium. The number of protons in an atom is very unique.

  • The number of protons is called atomic number.
  • The periodic table of element is sorted based on the number of protons i.e atomic numbers each element have.
  • Checking the periodic table, Americium is located in the f-block on the periodic table.
  • It has an atomic number of 95.

Learn more:

Periodic table brainly.com/question/8543126

#learnwithBrainly

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Calculate number of moles in 86.4 g of Ni
Ira Lisetskai [31]
Number of moles = mass of Ni /molecular mass of Ni

mass of nickel = 86.4 g
molecular mass of nickel = 58.69
number of moles of Ni in 86.4 g
=86.4/58.69
=1.472 mol  
(rounded to four significant figures instead of three because the first digit of the answer starts with a 1).
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3 years ago
Structural Formulas for Covalent Molecules
rosijanka [135]

Answer:

  1. CFJA17
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  3. GJA561
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  6. DG56
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Describe an adaptation to a plant's life cycle and explain how this adaptation helps the plant survive. (2 points)
dusya [7]

Answer:

Aquatic plants that live underwater have leaves with large air pockets inside that allow the plant to absorb oxygen from the water.

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________ is a measure of the amount of matter in an object.
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Mass i think hope and this helps u
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If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
Nikolay [14]

Answer:

0.036 M of CH_{3} COOH

Explanation:

It is an example of acid-base neutralization reaction.

KOH  + CH_{3} COOH  ----> CH_{3} COO^{-} K^{+}   +   H_{2}O

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= \frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

M_{1}V_{1} =M_{2}V_{2}------------------------------(1)

where

M_{1}= Molarity of Acid

V_{1}= Volume of Acid

M_{2}= Molarity of Base

V_{2}= Volume of Base

M_{1}=0.3330 M

V_{1}=10.62 mL

V_{2}=98.2 mL

M_{2}=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =M_{2}  × 98.2  

M_{2}=\frac{0.3330*10.62}{98.2}

M_{2}=0.036 M

3 0
2 years ago
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