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3 years ago

The natural source of acidity in rain water is _____. carbonic acid sulfuric acid nitric acid all of the above

2 answers:

8 0

<span>The natural source of acidity in rain water is all of the above. This is due to presence and abundance of carbon dioxide, nitrogen oxide, and sulfur dioxide in the atmosphere that can dissolve in rain water. Unpolluted rain water is made acidic due to CO2 and H2O in the air that forms carbonic acid.

Nitrogen oxide is mainly present due to the nitrogen fixation caused by lightning, while sulfur dioxide is mainly present due to volcanic eruptions. Other sources such as human activity can also contribute to acid rain. </span>

vovangra [49]3 years ago

6 0

Answer:

The answer would be (a) carbonic acid.

Explanation:

I just did this in one of my lessons and it was correct.

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Calculate the average reaction rate expressed in moles h2 consumed per liter per second

djyliett [7]

Answer:

Average rate of reaction expressed in moles H₂ consumed per liter per second = 0.0025 M/s = 0.0025 mol/L.s

Explanation:

The complete, correct Question, is presented in the attached image to this answer.

The average rate of reaction in terms of the reactant is defined as the total amount of reactant consumed over a period of time divided by total period of time.

Mathematically,

Average rate of reaction = (change in concentration of H₂ over a period of time) ÷ (total period of time)

Average rate of reaction = (-ΔC)/(Δt)

The minus sign is there because the concentration of reactants reduce with time.

change in concentration of H₂ = -ΔC

= -(0.02 - 0.03) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s

We could solve for the average rate of reaction expressed in moles Cl₂ consumed per liter per second

change in concentration of Cl₂ = -ΔC

= -(0.04 - 0.05) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s = 0.0025 mol/L.s

Hope this Helps!!!

8 0

4 years ago

In which direction does the wind blow from during a sea breeze

Nadusha1986 [10]

Answer:

Sea breeze moves from the areas of higher pressure on the water in the direction of the areas of lower pressure on land.

Explanation:

Sea breeze moves from the areas of higher pressure on the water in the direction of the areas of lower pressure on land. Whereas, land breeze blows from the areas of higher pressure on land to the areas of lower pressure on water.

3 0

3 years ago

C12H22O11 + 11 H2SO4 → 12 C + 11 H2SO4 + 11 H2O

BlackZzzverrR [31]

Answer:
T<span>he gaseous product of this reaction is water (Option-A).

Explanation:
This is a very interesting experiment. Take sugar in a beaker and add concentrated Sulfuric Acid into it. After a while an exothermic reaction will initiate with the formation of Carbon Black and Water vapors. You will observe the formation of hard and hot stem like body which is completely Black. This blackness is due to C and the water vapors will eliminate in the form of steam as the temperature has arised.</span>

5 0

3 years ago

Which of the following statements is true? A) The iron atom is best considered to be a solid. B) The mercury atom is best consid

shepuryov [24]

I believe the correct response would be D. At least 2 of the above statements are correct.

3 0

3 years ago

Read 2 more answers

Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a

GrogVix [38]

Answer:

The calorie content of 65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium) + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41 * (65/15) = 326.78 cal

8 0

3 years ago