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statuscvo [17]
3 years ago
10

Can anyone help me fill out this box please? im offering 82 points :)

Chemistry
1 answer:
goblinko [34]3 years ago
6 0

Answer:

I don't know. I am really, really sorry I am in 9th grade and i really did try.

Explanation:

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2 A(g) + B(g) ⇄ 2 C(g)
worty [1.4K]

Answer:

(C) substance B is not involved in the rate-determining step of the mechanism but is involved in subsequent steps.

Explanation:

A. Is incorrect because if the order of the reaction with respect B was one then the rate would increase by the same multiple that B is increased by.

B. If B is reactant then it must be involved in the mechanism of the reaction and in the formation of the product

D. If B was a catalyst then increasing it's amount would affect the rate

E. That is just factually untrue. Effect of reactants on rates can only be found experimentally, not stoichiometrically.

7 0
3 years ago
Neha and Reha are playing see-saw. Neha is sitting 60 cm away from the fulcrum and Reha is sitting 40 cm away from the fulcrum.
stich3 [128]

Answer:

Reha should apply 540 N to lift Neha.

Explanation:

L = 360 N

LD  = 60 m

E =?

ED = 40m

NOW

L * LD = E * ED

360 *60 = E*40

21600/40 = E

540 N = E

4 0
3 years ago
Give examples of Elements.
pishuonlain [190]

Answer: oxygen, hydrogen, sodium, chlorine, lead, iron. Examples of compounds include water ( or hydrogen oxide ) H2O; and Sodium Chloride, NaCl.

Explanation: plz mark brainest

8 0
4 years ago
Read 2 more answers
In the scientific process what is the purpose of the experiment
jasenka [17]
A to test the hypothesis
6 0
3 years ago
During a titration, the pH of an analyte solution containing HA(aq) is 3.92 and the ratio of [A–]/[HA] is 0.41. What is the Ka o
Solnce55 [7]

Answer:

Ka=4.71x10^{-4}

Explanation:

Hello there!

In this case, according to the Henderson-Hasselbach equation, it is possible to write:

pH=pKa+log(\frac{[A^-]}{[HA]} )

Next, since we are given the pH and the [A–]/[HA] ratio, we can solve for the pKa as shown below:

pKa=pH-log(\frac{[A^-]}{[HA]} )

Now, we plug in the values to obtain:

pKa=3.92-log(0.41 )\\\\pKa=3.33

Next, Ka is:

Ka=10^{-pKa}=10^{-3.33}\\\\Ka=4.71x10^{-4}

Best regards!

3 0
3 years ago
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