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Makovka662 [10]
3 years ago
14

An object's speed is the distance it travels ____ the amount of time it takes

Chemistry
1 answer:
MissTica3 years ago
3 0
Speed = distance / time

I think the answer would be "divided by"
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How many molecules of oxygen are in 3.0 moles of oxygen?
jenyasd209 [6]

Answer:

There are 18 moles of oxygen in 3.0 mole of glucose...

Explanation:

Does it help???

5 0
3 years ago
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Samarium-146 has a half-life of 103.5 million years. After 1.035 billion years, how much samarium-146 will remain from a 205-g s
BaLLatris [955]

Answer : The correct option is, 0.200 g

Solution :

As we know that the radioactive decays follow first order kinetics.

First we have to calculate the rate constant of a samarium-146.

Formula used :

t_{1/2}=\frac{0.693}{k}

Putting value of t_{1/2} in this formula, we get the rate constant.

103.5\times 10^6=\frac{0.693}{k}

k=6.6\times 10^{-9}year^{-1}

Now we have to calculate the original amount of samarium-146.

The expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = 6.6\times 10^{-9}year^{-1}

t = time taken for decay process  = 1.035\times 10^{9}years

a = initial amount of the samarium-146 = 205 g

a - x = amount left after decay process  = ?

Putting values in above equation, we get the value of initial amount of samarium-146.

6.6\times 10^{-9}=\frac{2.303}{1.035\times 10^{9}}\log\frac{205}{a-x}

a-x=0.200g

Therefore, the amount left of the samarium-146 is, 0.200 g

4 0
4 years ago
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What forces typically hold separate molecules together?
Lelechka [254]

Answer:

Intermolecular forces.

Explanation:

5 0
4 years ago
4 Nitrogen monoxide reacts with oxygen like this:
olga2289 [7]

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

<h3>Further explanation</h3>

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

a.

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

\tt \dfrac{1}{2}\times 1=0.5

b.

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

\tt \dfrac{1}{2}\times 50~cm^3=25~cm^3

c.

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³

6 0
3 years ago
If a block has a density of 1.8 g/ml, will it float?
Natali [406]

Answer:

No it won't.

Explanation:<em> </em>If GREATER than 1 g/cm3, it will SINK in water.

7 0
4 years ago
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