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yaroslaw [1]
3 years ago
9

A hot air balloon moves vertically upwards at constant velocity of 1.5 m s−1 . A person standing on the ground below throws a ba

ll towards the balloon with vertical velocity of 10 m s−1. The ball does not reach the balloon.
Calculate the time at which the ball comes closest to the balloon after it is thrown.

(You may ignore air resistance. Take the acceleration due to gravity to be 10 m s−2.)
Physics
1 answer:
serg [7]3 years ago
8 0

Answer:

idk srry

Explanation:

i wish I could help you out

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If two objects A and B have the same kinetic energy but A has three times the momentum of B, what is the ratio of their inertias
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- The momentum of an object is given by p=mv

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In this problem, we have:

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- p_A = 3 p_B (A has three times the momentum of B)

Re-writing both equation we have:

\frac{1}{2}m_A v_A^2 = \frac{1}{2}m_B v_B^2\\m_A v_A = 3 m_B v_B

If we divide first equation by second one we get

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So, B has 9 times more mass than A, and so B has 9 times more inertia than A, and their ratio is:

\frac{I_B}{I_A}=\frac{km_B}{km_A}=\frac{9m_A}{m_A}=9

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