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yaroslaw [1]
2 years ago
9

A hot air balloon moves vertically upwards at constant velocity of 1.5 m s−1 . A person standing on the ground below throws a ba

ll towards the balloon with vertical velocity of 10 m s−1. The ball does not reach the balloon.
Calculate the time at which the ball comes closest to the balloon after it is thrown.

(You may ignore air resistance. Take the acceleration due to gravity to be 10 m s−2.)
Physics
1 answer:
serg [7]2 years ago
8 0

Answer:

idk srry

Explanation:

i wish I could help you out

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Answer:

Do = density of obect      Dw = density of water

Weight of object = V g Do

Weight of water = V g Dw

F = m a = V Do a = V g Do - V g Dw

Acceleration of object = mass * force on object

Do (g - a) = Dw g

Do = Dw ( 1 / (1 - a / g) = 1000 * 1 / (1 - 3.75 / 9.80)  kg/m^3

Do = 1441 kg / m^3

If no acceleration then density of object = density of water

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The orbital speed of the space shuttle is 2.12 x 10⁴ m/s.

<h3>Orbital speed of the space shuttle</h3>

The orbital speed of the space shuttle is calculated as follows;

V = \sqrt{\frac{GM}{r} }

where;

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Learn more about orbital speed here: brainly.com/question/22247460

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