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Llana [10]
3 years ago
11

A 346.9 ml sample of carbon dioxide was heated to 381 k. if the volume of the carbon dioxide sample at 381 k is 596.2 ml, what w

as its temperature at 346.9 ml?
Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0
The  temperature  at  346.9  ml  is calculated  using   Charles   law  formula

that  is   V1/T1= V2/T2

T1=  381   K
V1= 596.2 ml
V2  = 346.9  ml
T2=?
by  making  T2  the  subject   of  the  formula   T2= T1V2/V1

T2  = 381  x  346.9/596.2  = 221.69  K

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8 0
3 years ago
Please I need help on these 3 questions. Thank You.​
Liula [17]

1.

V = 200 mL (volume)

c = 3 M = 3 mol/L (concentration)

First we convert mL to L:

200 mL = 0.2 L

Then we calculate the moles using the formula: n = V × c = 0.2 L × 3 mol = 0.6 mol

Finally, we just use the molar mass of CaF2 to calculate the actual mass:

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2.

For this question the steps are exactly like the first question.

V = 50mL = 0.05 L

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3.

The steps for this question are the opposite way.

m(K2CO3) = 250 g

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