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Llana [10]
3 years ago
11

A 346.9 ml sample of carbon dioxide was heated to 381 k. if the volume of the carbon dioxide sample at 381 k is 596.2 ml, what w

as its temperature at 346.9 ml?
Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0
The  temperature  at  346.9  ml  is calculated  using   Charles   law  formula

that  is   V1/T1= V2/T2

T1=  381   K
V1= 596.2 ml
V2  = 346.9  ml
T2=?
by  making  T2  the  subject   of  the  formula   T2= T1V2/V1

T2  = 381  x  346.9/596.2  = 221.69  K

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As, all the chlorine in the sample is precipitated to silver chloride. So, the mass of chlorine in silver chloride will be equal to the mass of chlorine present in the sample.

To calculate the mass of chlorine in given mass of AgCl, we apply unitary method:

In 143.32 g of silver chloride, mass of chlorine present is 35.45 g

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\%\text{ composition of chlorine}=\frac{0.3335g}{0.5922g}\times 100=56.31\%

Hence, the mass percent chlorine in pure chloride compound is 56.31 %.

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