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Llana [10]
3 years ago
11

A 346.9 ml sample of carbon dioxide was heated to 381 k. if the volume of the carbon dioxide sample at 381 k is 596.2 ml, what w

as its temperature at 346.9 ml?
Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0
The  temperature  at  346.9  ml  is calculated  using   Charles   law  formula

that  is   V1/T1= V2/T2

T1=  381   K
V1= 596.2 ml
V2  = 346.9  ml
T2=?
by  making  T2  the  subject   of  the  formula   T2= T1V2/V1

T2  = 381  x  346.9/596.2  = 221.69  K

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3 years ago
Explain how the Rutherford gold foil experiment correctly advanced atomic theory away from the plum pudding model?
Rudiy27

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Law Incorporation [45]

Answer:

(a) W

(b) X

(c) Y

Explanation:

Let's consider the following table with melting and boiling points for 4 substances.

Substance     Melting Point (°C)       Boiling Point (°C)

     W                       -7                                  60

     X                       660                              2500

     Y                        180                               1330

     Z                         115                                445

Let's consider that:

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(a) Which substance is a gas at 100°C?

At 100 °C, W is above the boiling point

(b) Which substance is a liquid for the largest range of temperature?

The largest difference between the melting point and the boiling point is that of X: 2500 - 660 = 1840.

(c) Which substance is liquid at 1000 °C and a gas at 2000°C?​

Y is between the melting and the boiling point at 1000 °C and above the boiling point at 2000 °C.

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