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Llana [10]
3 years ago
11

A 346.9 ml sample of carbon dioxide was heated to 381 k. if the volume of the carbon dioxide sample at 381 k is 596.2 ml, what w

as its temperature at 346.9 ml?
Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0
The  temperature  at  346.9  ml  is calculated  using   Charles   law  formula

that  is   V1/T1= V2/T2

T1=  381   K
V1= 596.2 ml
V2  = 346.9  ml
T2=?
by  making  T2  the  subject   of  the  formula   T2= T1V2/V1

T2  = 381  x  346.9/596.2  = 221.69  K

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We do not perform the titration while the sample is at its original temperature because reaction is too slow at original temperature and requires high activation energy.

A titration is a method where the concentration of an unknown solution is ascertained by comparing it to a solution of known concentration. The analyte (the unknown solution) is typically added in a known amount to the titrant (the known solution) from a buret until the reaction is finished.

The slow energy step in the reaction process may require a high activation energy, and the proportion of activated molecules needed to reach this reaction at room temperature or original temperature is too low, so most molecules cannot cross this peak. As a result, the reaction at room temperature proceeds very slowly (the final product is not reached). Heat can enhance the proportion of active molecules and catalyse a larger-scale reaction.

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