Question

. Calculate the molarity of 2.00 L of a glucose solution that contains 582.0 g of glucose (C6H12O6).

Answer 1

Answer:

$M=1.62M$

Explanation:

Hello.

In this case, since the molarity is computed by the division of the moles of the solute by the volume of the solution in liters:

$M=\frac{n_{solute}}{V_{solution}}$

We first compute the moles of glucose (molar mass 180 g/mol) as shown below:

$n_{solute}=582.0g*\frac{1mol}{180g} =3.233mol$

Therefore, the molarity turns out:

$M=\frac{3.233mol}{2.00L}\\ \\M=1.62M$

Best regards.