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scoundrel [369]
2 years ago
12

. Calculate the molarity of 2.00 L of a glucose solution that contains 582.0 g of glucose (C6H12O6).

Chemistry
1 answer:
zlopas [31]2 years ago
3 0

Answer:

M=1.62M

Explanation:

Hello.

In this case, since the molarity is computed by the division of the moles of the solute by the volume of the solution in liters:

M=\frac{n_{solute}}{V_{solution}}

We first compute the moles of glucose (molar mass 180 g/mol) as shown below:

n_{solute}=582.0g*\frac{1mol}{180g} =3.233mol

Therefore, the molarity turns out:

M=\frac{3.233mol}{2.00L}\\ \\M=1.62M

Best regards.

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