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GarryVolchara [31]
3 years ago
12

What do mechanical waves carry?

Physics
1 answer:
Wewaii [24]3 years ago
7 0
A mechanical wave is a wave that is not capable of transmitting its energy through a vacuum. Mechanical waves require a medium in order to transport their energy from one location to another. A sound wave is an example of a mechanical wave.
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Which theory best explains the present arrangement of continents oceans and landforms on earth? A the Pangaea theory B The conti
solong [7]

Plate Tectonic Theory

3 0
3 years ago
Ali mixes 20g of Sodium Chloride in 100g of water at 15 Degree °C. Calculate the mass of the solution
Lera25 [3.4K]

Answer:

The mass of the solution is 120 g.

Explanation:

The mass of the solution is given by:

m_{sol} = m_{1} + m_{2}

Where:

m_{sol}: is the mass of the solution

m_{1}: is the mass of the solvent

m_{2}: is the mass of the solute

In the solution, the solvent is the majority compound (in mass) and the solute is the minority (in mass), so the solvent is the water and the solute is sodium chloride.          

Hence, the mass of the solution is:

m_{sol} = m_{1} + m_{2} = 100 g + 20 g = 120 g  

I hope it helps you!                  

7 0
3 years ago
Which two forces operate over the longest distances?
Harman [31]

Answer:

D Electromagnetic and gravitational

5 0
3 years ago
What remains constant during the trajectory of an object
S_A_V [24]

Answer:

projectile

Explanation:

3 0
3 years ago
A point charge A of charge +4micro coloumb and another B of -1 micro coloumb are placed at a distance in air 1m apart then the d
andrew11 [14]

Answer:

Explanation:

Given that,

A point charge is placed between two charges

Q1 = 4 μC

Q2 = -1 μC

Distance between the two charges is 1m

We want to find the point when the electric field will be zero.

Electric field can be calculated using

E = kQ/r²

Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.

Then, the magnitude of the electric at point x is zero.

E = kQ1 / r² + kQ2 / r²

0 = kQ1 / x²  - kQ2 / (1-x)²

kQ1 / x² = kQ2 / (1-x)²

Divide through by k

Q1 / x² = Q2 / (1-x)²

4μ / x² = 1μ / (1 - x)²

Divide through by μ

4 / x² = 1 / (1-x)²

Cross multiply

4(1-x)² = x²

4(1-2x+x²) = x²

4 - 8x + 4x² = x²

4x² - 8x + 4 - x² = 0

3x² - 8x + 4 = 0

Check attachment for solution of quadratic equation

We found that,

x = 2m or x = ⅔m

So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.

5 0
3 years ago
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