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ivanzaharov [21]
3 years ago
8

Please Help!!!!!! What is the acceleration of a car between 2 and 5 seconds? Hint: Acceleration is a change in speed and directi

on.
A. 15 m/s2

B. 0 m/s2

C. 5 m/s2

D. 30 m/s 2

Physics
2 answers:
Ghella [55]3 years ago
5 0

Answer : B.  0 m/s∧2

Now we know that velocity = distance/ time

And acceleration = velocity/time.


From the graph we see that at the time interval 2 secs,the distance travelled is 10 m. Hence the velocity(v1) =10/2 = 5m/s.

From the graph we see that at the time interval 5 secs,the distance travelled is 25 m. Hence the velocity (v2) =25/5 = 5m/s.

Now acceleceration between the time interval of 2 ad 5 secs is calculated as

(v1-v2)/t2-t1 = (5-5)/(5-2) = 0 m/s∧2

uysha [10]3 years ago
5 0

Answer:

B. 0 m/s 2

Explanation:

See picture

Give me brainliest if i was right!

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Which of the following is not true of a conductor? A. It is used in electrical circuits. B. It allows easy passage of moving cha
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Homes with multiple bathrooms have outlets connected in series with a red reset button in the system
dybincka [34]

Homes with multiple bathrooms have outlets connected in series with a red reset button in the system. The reason for this circuit design is to prevent electrocution.

<h3>What is red reset button?</h3>

The water heater's reset switch provided on the upper thermostat of an electric water heater. If the button is on, the switch would have tripped and the reset is required.

To prevent any kind of injury or killing of a person by electric shock is called as the electrocution. This can be prevented only by outlets connected in series with a red reset button.

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8 0
2 years ago
A soccer ball with a mass of 0.45 kg is kicked and is moving at 8.9 m/s. Find the kinetic
strojnjashka [21]

Answer:

17.82J

Explanation:

Kinetic energy = 1/2 mv^2

Given

Mass M = 0.45kg

Velocity v = 8.9m/s

Therefore,

K.E. = 1/2 x 0.45 x (8.9)^2

= 1/2 x 0.45 x (8.9 x 8.9)

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3 0
3 years ago
A dragster race car can accelerate from rest to incredible speeds. In one case a dragster is able to finish the 305 m run in 3.6
Dafna1 [17]

Answer:

45.89m/s²

Explanation:

Given

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To get the acceleration during this run, we will apply the equation of motion:

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Substitute the given parameters into the formula and calculate the value of a

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Hence the average acceleration during this run is 45.89m/s²

4 0
3 years ago
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