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ivanzaharov [21]
3 years ago
8

Please Help!!!!!! What is the acceleration of a car between 2 and 5 seconds? Hint: Acceleration is a change in speed and directi

on.
A. 15 m/s2

B. 0 m/s2

C. 5 m/s2

D. 30 m/s 2

Physics
2 answers:
Ghella [55]3 years ago
5 0

Answer : B.  0 m/s∧2

Now we know that velocity = distance/ time

And acceleration = velocity/time.


From the graph we see that at the time interval 2 secs,the distance travelled is 10 m. Hence the velocity(v1) =10/2 = 5m/s.

From the graph we see that at the time interval 5 secs,the distance travelled is 25 m. Hence the velocity (v2) =25/5 = 5m/s.

Now acceleceration between the time interval of 2 ad 5 secs is calculated as

(v1-v2)/t2-t1 = (5-5)/(5-2) = 0 m/s∧2

uysha [10]3 years ago
5 0

Answer:

B. 0 m/s 2

Explanation:

See picture

Give me brainliest if i was right!

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Examine the scenario.
vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

distance: 40 km

speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

velocity: 5 km/h north

is wrong, because the car is moving south, not north.

So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

a=\frac{v-u}{t}

where

v = 40 km/h is the final velocity

u = 0 is the initial velocity

t = 5 s is the time

Substituting,

a=\frac{40 km/h-0}{5 s}=8 km/h/s

And since the sign is positive, the direction is the same as the velocity (south).

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4 years ago
What is the wavelength of a proton traveling at a speed of 6.21 km/s? what would be the region of the spectrum for electromagnet
lukranit [14]
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How do elastic objects behave when different forces are applied?
eimsori [14]
They both move in the opposite direction in which they hit
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Audible wavelengths. the range of audible frequencies is from about 20.0 hz to 2.00×104 hz . what is range of the wavelengths of
BabaBlast [244]
Given:
f1 = 20 Hz 
f2 = 20000 Hz
speed of sound at 20 degrees celcius = 343 m/s

Solution:

for f1 = 20 Hz,

Using the equation:

lambda = speed of sound / f1 = 343 / 20 = 17.15 m 

For f2: 

lambda = speed of sound / f2 = 343 / 20000 = 0.01775 m

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