1. Air resistance (therefore, the air density, shape (aerodynamic or not), and surface area affected
2. The gravitational acceleration constant (g = 9.8 m/s^2 on Earth)
To break this problem down, let's start with what we know. The equation given finds one component of the velocity and multiplies it by the change in time. This will not find the acceleration that the first two answers say it will, meaning that the answer isn't A or B.
That leaves us with the final two answers, C and D. If the projectile was launched horizontally and we were trying to find the horizontal displacement, we wouldn't need to use cosθ to find the horizontal velocity, meaning that our answer is most likely C) <span>the horizontal displacement of a projectile launched at an angle!</span><span />
Answer:
it decreases in size
Explanation:
The reason why this happens is simply just condensation. unlike when water is boiling, that is evaporating
Answer:
(a) False
(b) True
(c) True
(d) True
(e) True
(f) True
Explanation:
(a) Maxwell's equations not only applies to constant fields but it applies to both the fields, i.e., Time variant field as well as Time Invariant field.
(b) We make use of the Modified form of the Ampere's law and Faraday's Law to derive the wave equation.
(c) Electromagnetic waves contains both the electric and magnetic fields and these fields oscillates at an angle of
to the direction of wave propagation.
(d) In free space both the electric and magnetic fields are in phase while considering electromagnetic waves.
(e) In free space or vacuum, the expression for the speed of light in terms of electric and magnetic field is given as:

Thus the ratio of the magnitudes of the electric and magnetic field vectors are equal to the speed of light in free space.
(f) In free space or in vacuum the energy density of the electromagnetic wave is divided equally in both the fields and hence are equal.
Answer:
The value of current through the rod becomes half

Explanation:
As per Ohm's law we know that the current through a resistor is given as

here we know that

here we know that the length of the cylinder is L and area is A so the value of current through the rod is given as

now we have change the length of the conductor to twice of initial value and rest all parameters will remain the same
so we will have

now from above two equations we have

so new current will become
