Answer:
The value of F= - 830 N
Since the force is negative, it implies direction of the force applied was due south.
Explanation:
Given data:
Mass = 1000-kg
Distance, d = 240 m
Initial velocity, v1 = 20.0 m/s
Final velocity, v2 = 0 (since the car came to rest after brake was applied)
v2²= v1² + 2ad (using one of the equation of motion)
0= 20² + (2 x a x 240)
0= 400 + 480 a
a = - 400/480
a = - 0.83 m/s²
Then, imputing the value of a into
F = ma
F = 1000 kg x ( - 0.83 m/s²)
F= - 830 N
The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.
Answer:
8.6 miles
Explanation:
We need to calculate the components of the total displacement along the east-west and north-south directions first.
In the first part, Erica moves 5.2 miles at 25∘ north of east. So the components of this displacement along the two directions are:
East: 
North: 
In the second part, Erica moves 5.0 miles north. So, the components of this displacement are:
East: 
North: 
So the components of the total displacement are
East: 
North: 
Therefore the magnitude of the displacement, which is the straight-line distance from the starting point to the end of the race, is

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