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S_A_V [24]
3 years ago
13

Which type of radio waves have the highest frequency and are used in radar detection? microwaves x-rays waves infrared waves gam

ma waves
Physics
2 answers:
goldfiish [28.3K]3 years ago
5 0

Answer: Microwaves

Explanation:

RADAR stands for radio detection and ranging.  Radio waves range from 300 GHz to 30 Hz. Modern radar uses higher frequency of waves for detection. These waves are microwaves (300 MHz-300 GHz). Microwaves are types of radio waves and are used in the radar detection.

The electromagnetic wave which has highest frequency is gamma wave but it is not used for radar detection.

Hence, the correct answer is microwaves are the type pf radio waves which have the highest frequency and are used in radar detection.

amm18123 years ago
5 0
<span>microwaves are a type of radio waves used in radar detection and they have the highest frequency.</span>
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Although the evidence is weak, there has been a concern in recent years over possible health effects from the magnetic fields ge
sergey [27]

Answer:

a

The magnetic field strength is  B = 2 \mu T

Explanation:

From the question we are told that

             The  length line   above the ground  is  R = 20m

              The current of the line is  I  = 200A

              The voltage of the line is V = 110kV

Generally magnetic field strength is mathematically represented as

              B = \frac{\mu_o I}{2 \pi R}

Where  \mu_0 is the permeability of free space  = 4\pi * 10^{-7} N/A^2

             B = \frac{(4\pi * 10^{-7} N/A^2) *200}{2 \pi *20}

                = (2.0*10^{-7})[\frac{200}{20} ]

               = 2*10^{-6}T

              = 2 \mu T

Earths magnetic field is approximately given as 50 \mu T

   So the percentage would be

                           = \frac{Magnetic \ Field \ Intensity \ Of  \ Line}{Earth's \ Magnetic \ Field} * 100

                          = \frac{2 \mu T }{50 \mu T } * 100

                          =4%            

         

           

             

               

7 0
3 years ago
A 1-lb block and a 100-lb block are placed side by side at the top of a frictionless hill. Each is given a very light tap to beg
qwelly [4]

Answer:

(c). The two blocks end in a tie

Explanation:

the reason being the absence of any resistance offered to both of the blocks.

if the slope of the hill is for instance 60 deg.

then the acceleration in absence of any resistance is a= 9.81sin(60)

since the acceleration is same then both of the blocks will reach at the same instant

4 0
3 years ago
Calculate the period of a satellite orbiting the Moon, 98 kmkm above the Moon's surface. Ignore effects of the Earth. The radius
beks73 [17]

Answer:

3.6*10^18s

Explanation:

To find the period of the satellite

We need to apply kephler's third law

Which is

MP² = (4π²/G) d³

d=semi-major axis which is the distance from center of moon = 98km+1740km = 1838km

where M= mass of the moon = 7.3x10^22kg

P=period

G=newtonian gravatational constant= 6.67x10^-11

To find the Period solve for P

P = √[(4π²/G M)xd³]

P=√(4 π²/6.67x10^-22*7.3x10^22kg) x (1.838x10^6m)³]

= 3.6*10^18s

6 0
3 years ago
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Answer:

Explanation:

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6 0
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igomit [66]

Answer:

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Explanation:

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