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S_A_V [24]
3 years ago
13

Which type of radio waves have the highest frequency and are used in radar detection? microwaves x-rays waves infrared waves gam

ma waves
Physics
2 answers:
goldfiish [28.3K]3 years ago
5 0

Answer: Microwaves

Explanation:

RADAR stands for radio detection and ranging.  Radio waves range from 300 GHz to 30 Hz. Modern radar uses higher frequency of waves for detection. These waves are microwaves (300 MHz-300 GHz). Microwaves are types of radio waves and are used in the radar detection.

The electromagnetic wave which has highest frequency is gamma wave but it is not used for radar detection.

Hence, the correct answer is microwaves are the type pf radio waves which have the highest frequency and are used in radar detection.

amm18123 years ago
5 0
<span>microwaves are a type of radio waves used in radar detection and they have the highest frequency.</span>
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A rock is thrown horizontally from a bridge with a speed of 29.0 m/s. if the rock is 23.7 meters above the river at the moment o
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It would be 1.5 meters im sure form that distance to me is that nswe

7 0
3 years ago
A steel beam of mass 1975 kg and length 3 m is attached to the wall with a pin that can rotate freely on its right side. A cable
Nuetrik [128]

Answer:

a) 29062.125 N·m

b) 0 N·m

c) Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) T = 11186.02 N

Explanation:

We are given

Beam mass = 1975 kg

Beam length = 3 m

Cable angle = 60° above horizontal

a) We have the formula for torque given as follows;

Torque about the pin = Force × Perpendicular distance of force from pin

Where the force = Force due to gravity or weight, we have

Weight = Mass × Acceleration due to gravity = 1975 × 9.81 = 19374.75 N

Point of action of force = Midpoint for a uniform beam = length/2

∴ Point of action of force = 3/2 = 1.5 m

Torque due to gravity = 19374.75 N × 1.5 m = 29062.125 N·m

b) Torque about the pinned end due to the contact forces between the pin and the beam is given by the following relation;

Since the distance from pin to the contact forces between the pin and the beam is 0, the torque which is force multiplied by perpendicular distance is also 0 N·m

c) To find the expression for the tension force, T we find the sum of the moment forces about the pin as follows

Sum of moments about p is given as follows

∑M = 0 gives;

T·sin(θ) × L= M×L/2×g

Therefore torque due to tension is given by the following expression

Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) Plugging in the values in the torque due to tension equation, we have;

3\times Tsin60 = \frac{1975\times 3\times 9.81}{2} = 29062.125

Therefore, we make the tension force, T the subject of the formula hence

T= \frac{29062.125}{3 \times sin(60)} = 11186.02 N

8 0
3 years ago
List the differences between a radio EM wave and a visible light EM wave
just olya [345]

1). A radio EM wave has a frequency somewhere between 10 KHz and 300 GHz, whereas a visible light EM wave has a frequency somewhere between 428,000 GHz and 790,000 GHz.

2).  A radio EM wave has a wavelength somewhere between 1 mm and 30 km, whereas a visible light EM wave has a wavelength somewhere between 380-700 nanometers.

7 0
3 years ago
A plane is flying horizontally at a height of 500 m and a constant speed of 429 km/h when an object is projected downward at an
Strike441 [17]

Answer:  the average vertical component of velocity between the object's release and its striking the ground is 49.5 m/s or 178 km/h


Explanation:


1) The motion of an object under the action of gravity, when air resistance is neglected is called projectile motion. The path is a curve with the form of  a parabola.


2) The equations that rule that motion are:

  • Horizontal speed:
  • Vx = Vox = constant.
  • In this case it is the same horizontal speed of the plane at the moment when the object was proyected. Vx = 429 km/h.
  • Vertical speed:

         Vy = Voy + gt

         d = yo - Voy×t - gt² / 2

         Vy² = Voy² - 2gd

  • Since, you know Voy =0, g = 9.81 m/s², and d = 500m, you can use the last equation, leading to:

        Vy² = 2(9.81m/s²)(500m) = 9,810 m²/s² ⇒ Vy = √(9,810 m²/s²) = 99 m/s


3) As per definition the average velocity is displacement / time, so you need to find the time to reach the ground.

  • You can use the formula  Vy = Voy + gt
  • Clear t: t = (Vy - Voy) / g = (99 m/s - 0) / 9.81 m/s = 10.1s

  • Average vertical velocity = 500 m / 10.1s = 49.5 m/s.
  • You can convert to km/h: 49.5 m/s × 1km/1,000m × 3600s/h = 178 km/h

4) Conclusion: the average vertical component of velocity between the object's release and its striking the ground is 49.5 m/s or 178 km/h

8 0
3 years ago
"Your friend has a job as a pizza delivery person. She carries a few pizzas, weighing 20 N, up four flights of stairs , a height
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Answer:

600J

Explanation:

work done=newtons×distance

5 0
3 years ago
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