The electric potential between the two charges is 91.68 V.
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Electric potential between the two charges</h3>
The electric potential between the two charges is calculated as follows;
V = Ed
where;
- V is electric potential
- E is electric field
- d is the distance of the charge
Substitute the given parameters and solve for electric potential,
V = 573 N/c x 0.16 m
V = 91.68 V
Thus, the electric potential between the two charges is 91.68 V.
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Answer:
True
Explanation:
The statement is true because According to Schrödinger it's not possible to get the exact position of where an electron is located. However, he showed from an equation that we can at determine the most likely area where an electron will be and he said they are most likely to be in the most dense area of the clouds.
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Explanation:
The point P lies at a linear distance 1 m from the corner. Magnetic field due to current in wire Magnetic field due to current in wire. Applying Right hand thumb rule, the magnetic field at P is perpendicular to xy plane and into the plane of drawing (i.e. negative z-direction).
The problem describes the relationship of "bulb a" and "bulb b" to be in connected in series. When the switch is open then no current can flow, on the other hand, when it is closed, current will pass through.
When only "bulb a" is connected to the battery then more current is flowing to "bulb a" causing it to be bright.
Closing the switch would mean that "bulb b" is already included in the circuit and the battery will push small current to flow around the whole circuit. The more bulbs are connected, the harder for the current to flow because the resistance will be very high.
So the light of "bulb a" will be dimmer.