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algol [13]
3 years ago
8

A steel rope has a 25 mm diameter and density of 5000 kg/m^3. The largest tension it can withstand is 320,000 N. What is the lon

gest length of of this rope in m that can hang without breaking?
Physics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

longest length is 13304.05 m

Explanation:

given data

diameter = 25 mm

so radius r = 12.5 × 10^{-3} m

density = 5000 kg/m³

tension = 320000 N

to find out

longest length of of this rope

solution

we know that here tension is express as

T = m × g

and m is mass and g is  acceleration due to gravity

here mass = density × volume

and volume = π×r²×l

here r is radius and l is length

so T = density c volume  × g

put here value

320000 = 5000 × π×12.5² × 10^{-3} × l × 9.8

solve it we get length l

l = 13304.05

so longest length is 13304.05 m

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Joey drives along the 110 South freeway and notices a mile marker that reads 260 miles. He drives until he reaches the 150 mile
Nostrana [21]

Answer:

85 miles .

Explanation:

Displacement along the 110 South freeway = 260 - 150  =  110 miles

Displacement along the 110 North freeway = 150 - 175   = - 25 miles

Net displacement = 110 - 25 = 85 miles

So Joey's displacement from the 260 mile marker is 85 miles .

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3 years ago
Pitch is determined by the ____ of a sound wave.
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The answer is c .Frequency
8 0
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A 0.5-kilogram apple falls from a height of 2 meters to 1.50 meters. Ignoring frictional effects, what is the kinetic energy of
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The  final kinetic energy of the ball is 2.45 J

Explanation:

We can solve this problem by using the law of conservation of energy.

In absence of frictional effect, the mechanical energy of the apple must be conserved during the fall. So we can write:

U_i +K_i = U_f + K_f

where :

U_i is the initial potential energy, at the top

K_i is the initial kinetic energy, at the top

U_f is the final potential energy, at the bottom

K_f is the final kinetic energy, at the bottom

By explicing the potential energy, we can rewrite the equation as:

mgh_i + K_i = mgh_f + K_f

where:

m = 0.5 kg is the mass of the apple

g=9.8 m/s^2 is the acceleration of gravity

h_i = 2 m is the initial height

h_f=1.50 m is the final height

The initial kinetic energy is zero, since the ball starts from rest:

K_i = 0

Therefore we can solve the equation for K_f, the final kinetic energy of the ball:

K_f = mg(h_i-h_f)=(0.5)(9.8)(2-1.50)=2.45 J

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

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3 0
4 years ago
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On a highway curve with a radius of 46 meters, the maximum force of static friction that can act on a 1,200 kg car going around
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Answer:

v\approx 16.956\,\frac{m}{s}

Explanation:

The motion of the vehicule on a highway curve can be modelled by the following equation of equilibrium:

\Sigma F = f = m\cdot \frac{v^{2}}{R}

The maximum speed is:

v = \sqrt{\frac{f\cdot R}{m} }

v = \sqrt{\frac{(7500\,N)\cdot (46\,m)}{1200\,kg} }

v\approx 16.956\,\frac{m}{s}

7 0
4 years ago
For a standard production car, the highest road-tested acceleration ever reported occurred in 1993, when a Ford RS200 Evolution
Ann [662]

Answer:

a = 8.06 m/s²

Explanation:

The acceleration of this car can be found using the first equation of motion:

v_f = v_i + at\\\\a = \frac{v_f-v_i}{t}

where,

a = acceleration = ?

vf = final speed = 26.8 m/s

vi = initial speed = 0 m/s

t = time = 3.323 s

Therefore,

a = \frac{26.8\ m/s-0\ m/s}{3.323\ s}

<u>a = 8.06 m/s²</u>

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3 years ago
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