Answer:
Line the numbers from smallest to largest the subtract the smallest from the largest numbers.
Explanation:
  
        
             
        
        
        
The gas would also decrease in size since the container lost gas to decrease the size of the container.
        
             
        
        
        
Answer:
Explanation:
Part A) Using 
light intensity I= P/A 
A= Area= π (Radius)^2= π((0.67*10^-6m)/(2))^2= 1.12*10^-13 m^2
Radius= Diameter/2 
P= power= 10*10^-3=0.01 W 
light intensity I= 0.01/(1.12*10^-13)= 9*10^10 W/m^2 
Part B)  Using
I=c*ε*E^2/2
rearrange to solve for E=  ((I*2)/(c*ε))
((I*2)/(c*ε))
c is the speed of light which is 3*10^8 m/s^2
ε=permittivity of free space or dielectric constant= 8.85* 10^-12 F⋅m−1
I= the already solved light intensity= 8.85*10^10 W/m^2
amplitude of the electric field E=  (9*10^10 W/m^2)*(2) / (3*10^8 m/s^2)*(8.85* 10^-12 F⋅m−1)
(9*10^10 W/m^2)*(2) / (3*10^8 m/s^2)*(8.85* 10^-12 F⋅m−1)
---> E=  (1.8*10^11) / (2.66*10^-3) =
(1.8*10^11) / (2.66*10^-3) =  (6.8*10^13) = 8.25*10^6 V/m
(6.8*10^13) = 8.25*10^6 V/m     
   
 
        
             
        
        
        
Explanation:
F = Gm1m2/r^2
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