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azamat
3 years ago
11

“Dry ice” is the solid form of carbon dioxide. Determine the number of mass of CO2 gas in grams that are present in 61.8 L of CO

2 at STP.
_________________ g CO2. Do NOT enter unit. Report your final answer with 3 SFs.
Chemistry
1 answer:
Fofino [41]3 years ago
6 0

Answer:

Mass  = 121 g

Explanation:

Given data:

Mass in gram of CO₂ = ?

Volume = 61.8 L

Pressure = standard = 1 atm

Temperature = 273.15 K

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × 61.8 L = n ×0.0821 atm.L/ mol.K   × 273.15 k

61.8 L.atm = 22.42 atm.L/ mol × n

n = 61.8 L.atm /22.42 atm.L/ mol

n = 2.76 mol

Mass in gram:

Mass =  number of moles × molar mass

Mass = 2.76 mol × 44 g/mol

Mass  = 121 g

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shtirl [24]
Reaction equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Moles of Al(OH)₃:
moles = mass/Mr
= 1.51 / (27 + 17 x 3)
= 0.019
Molar ratio Al(OH)₃ : HCl = 1 : 3
Moles of HCl required = 0.019 x 3
=0.057
concentration = moles/volume
volume = 0.057 / 0.1
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3 0
3 years ago
Which types of particles are charged and located within the nucleus of an atom?
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Answer:

Protons, electron, and neutrons

Explanation:

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3 years ago
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8. How much heat is released when 85.0 g of steam condense to liquid water?
sergeinik [125]

Answer:

199920J

Explanation:

Given parameters:

Mass of steam  = 85g

Unknown:

Heat released when the liquid is condensed  = ?

Solution:

The heat released by the substance is given as;

         H  = mL

H is the heat released

m is the mass

L is the latent heat of steam  = 2352J/g

Heat released  = 85 x 2352  = 199920J

3 0
3 years ago
Formula for the compound that contains Mg2+ and O2-
jeka94

Answer:

MgO.

Explanation:

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7 0
3 years ago
If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

7 0
3 years ago
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