Answer:0.69
Explanation:
Coefficient of kinetic friction=f/R=61.8/90=0.69
We can substitute the given values into the equation for T, given the surrounding temperature T0 = 0, initial temperature T1 = 140, constant k = -0.0815, and time t = 15 minutes.
T = 0 + (140 - 0)e^(-0.0815*15) = 140e^(-1.2225) = 41.23°F
Answer:
106.03 meters
Explanation:
The height is given by the formula for motion under the influence of gravity.
h = -4.9t^2 +162.7
Height is 0 when ...
0 = -4.9t^2 +162.7
4.9t^2 = 162.7
t^2 = 162.7/4.9
t = √(162.7/4.9)
The horizontal distance traveled in that time is ...
(18.4 m/s)√(162.7/4.9) s ≈ 106.03 m
The object will strike the ground about 106.03 meters from the base of the cliff.
To solve this problem we will apply the concepts related to the conservation of kinetic energy and elastic potential energy. Thus we will have that the kinetic energy is

And the potential energy is

Here,
m = mass
v = Velocity
x = Displacement
k = Spring constant
There is equilibrium, then,
KE = PE

Our values are given as,

Replacing we have that


Therefore the speed of the cart is 2.19m/s
Answer:
x = 333.33 [m]
Explanation:
To solve this problem we must use the following kinematics equation.

where:
Vf = final velocity = 0
Vi = initial velocity = 20 [m/s]
a = desacceleration = 0.6 [m/s^2]
x = distance [m]
Note: the final speed is zero as the body finishes its movement.
Now replacing:
0 = (20)^2 - (2*0.6*x)
1.2*x = 400
x = 333.33 [m]