Which of the following describes the magnetic field lines produced by the straight wire carrying current? Magnetic field lines r
2 answers:
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Answer:
In order of increasing wavelength, the answer is:
(i) The gamma rays produced by a radioactive nuclide used in medical imaging
(iv) The yellow light from sodium-vapor streetlights
(v) The red light of a light emitting diode, such as in a calculator display
(ii) Radiation from an FM radio station at 93.1 MHz on the dial
(iii) A radio signal from an AM radio station at 680kHz on the dial
Explanation:
First, you have to know that the wavelength of a sinusoidal wave traveling at a constant speed is given by:
λ
Where λ is the wavelength, is the constant speed and
is the wave's frequency. In the case of electromagnetic radiation in free space, the constant speed is the speed of light.
From explained above, you can conclude that there is a proportionality relationship between the wavelength and the frequency, they are inversely proportional. That means: the highest frequency will have the shortest wavelength and vice-versa.
So, you have the following types:
(i) The gamma rays produced by a radioactive nuclide used in medical imaging
Frequency : Typically greater than Hz
(ii) Radiation from an FM radio station at 93.1 MHz on the dial
Frequency: 93.1 MHz
(iii) A radio signal from an AM radio station at 680 kHz on the dial
Frequency: 680 kHz
(iv) The yellow light from sodium-vapor streetlights
Frequency: Visible spectrum of approx. 508 - 526 THz
(v) The red light of a light-emitting diode, such as in a calculator display
Frequency: Visible spectrum of approx. 400 - 484 THz
Then, you have to organize them from the highest frequency to the smallest one (decreasing frequency), and as the highest frequency will have the shortest wavelength, you are going to have it organized in an increasing wavelength mode.
Then in order of increasing wavelength, the answer will be:
(i) , (iv), (v), (ii), (iii)
Answer:
9.82 × Hz
Explanation:
De Broglie equation is used to determine the wavelength of a particle (e.g electron) in motion. It is given as:
λ =
where: λ is the required wavelength of the moving electron, h is the Planck's constant, m is the mass of the particle, v is its speed.
Given that: h = 6.63 × Js, m = 2.50 kg, v = 2.70 m/s, the wavelength, λ, can be determined as follows;
λ =
=
=
= 9.8222 ×
The wavelength of the object is 9.82 × Hz.
Answer
given,
focal length of lens A = 5.77 cm
focal length of lens B= 27.9 cm
flies distance from mirror = 11.3 m
now,
Using lens formula
q =11.79 cm
image of lens A is object of lens B
distance of lens = 59.9 - 11.79 = 48.11
now, Again applying lens formula
q' =66.41 cm
hence, the image distance from the second lens is equal to q' =66.41 cm