Answer: theoretical yield of benzoin = 14.31g
Explanation:
2C7H6O => C14H12O2
molar mass of
benzaldehyde = 106g/mol
benzoin = 212g/mol
we start by calculating the mass of benzaldehyde (C7H6O):
mass of C7H6O = density x volume = 1.045x13.7 = 14.32g
number of moles of benzaldehyde= mass of benzaldehyde/ molar mass benzaldehyde.
number of moles of benzaldehyde = 14.32/106 = 0.135moles
Since benzaldehyde is the limiting reagent,
from the above equation,
2 moles of benzaldehyde produced 1 mole of benzoin
therefore, 0.135moles of of benzaldehyde will produce 0.135/2 = 0.0675 moles
mass of benzoin = number of moles of benzoin x molar mass benzoin = 0.0675 x 212 =14.31g
