So, parallel lines have the same slope, therefore a parallel line to 2x+12, will have the same slope as that one, so which is it?
so, we're really looking for the equation of a line whose slope is 2, and runs through -1,1.
![\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -1}}\quad ,&{{ 1}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 2 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-1=2[x-(-1)] \\\\\\ y-1=2(x+1)\implies y-1=2x+2\implies y=2x+3](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%5C%5C%0A%25%20%20%20%28a%2Cb%29%0A%26%28%7B%7B%20-1%7D%7D%5Cquad%20%2C%26%7B%7B%201%7D%7D%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%7B%7B%20m%7D%7D%3D%20%5Ccfrac%7Brise%7D%7Brun%7D%20%5Cimplies%202%0A%5C%5C%5C%5C%5C%5C%0A%25%20point-slope%20intercept%0A%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%7B%7B%20y_1%7D%7D%3D%7B%7B%20m%7D%7D%28x-%7B%7B%20x_1%7D%7D%29%7D%5Cimplies%20y-1%3D2%5Bx-%28-1%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-1%3D2%28x%2B1%29%5Cimplies%20y-1%3D2x%2B2%5Cimplies%20y%3D2x%2B3)
base is 8 times 8 because in a square all side lengths are the same, and to find the area of a square you multiply 2 sides. the square is the base in this so you use 8 times 8 as the base and you solve for height.
Divide 60 and 40 by muliples to get a perfect anwser
1) 3 spaces
2) 2 spaces
3) 4 spaces
4) 5 spaces
explanation: you look at the right side of each number, for example 14.95 x 0.41
how many numbers are to the right of the decimal?
The answer is 200 regular subscribers.
3×20=60 (Premium)
10×20=200 (Regular)
+--------
260 Subscribers
Don't feel afraid to ask more questions I find them fun to answer~!
