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3 years ago

GOOD POINTS HELP PLEASE IN SCIENCE

Physics

1 answer:

jeka943 years ago

6 0

The answer is c because a metallic bond Is 1. formed of the attraction between positively charged metal nuclei
2. and surrounding sea electrons

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A particle accelerator fires a proton into a region with a magnetic field that points in the +x-direction (a) If the proton is m

pochemuha

Answer:

a) -z direction, b) +z direction, c) F=0

Explanation:

The magnetic force is given by the expression

F = q v x B

the bold indicate vectors, this equation can be separated in its module

F = a v B sin θ

and where θ is the angles between the speed and the magnetic field.

The direction of the force can be found with the right-hand rule. For a positive charge, the thumb goes in the direction of speed, the fingers extended in the direction of the magnetic field and the palm points in the direction of the force, if the charge is negative the force is in the opposite direction.

a) Let's apply this to our case

the proton is positively charged

moves in the direction of + x

The magnetized field goes in the direction of y

therefore applying the right hand rule the force must be in the direction of the negative part of the z-axis (-z)

The right-hand rule is used to find this address.

b) in this case it indicates that the proton moves in the recode of -y

again we apply the right hand rule and the force is in the direction of + z

c) The proton moves in the x direction

In this case the force is zero because the angle between the field and the speed is zero and the sine is zero, therefore the force is zero

4 0

3 years ago

Can someone show me the work of this

Alik [6]

Answer:

use symbollab it will help u

Explanation:

7 0

3 years ago

What are the dimensions of F = ma?

nikdorinn [45]

Think its M1 L1 T-2. Hope it helped

5 0

3 years ago

Read 2 more answers

Two forces are acting on an object. The first force has magnitude F1=33.4 N and is pointing at an angle of θ1=23.8 clockwise fro

lesya [120]

Answer:

a)Fnx = -26.92 N

b)Fny= 8.4 N

c)Fex = 26.92 N

d)Fey = - 8.4 N

e)β = 18.34° clockwise from the positive x axis

Explanation:

Look at the attached graphic

a) What is the x component of the net force acting on the object?

Fnx:x component of the net force acting on the object

Fnx= F₁x+ F₂x

F₁x= 33.4*sin 23.8° = 13.48 N

F₂x= - 46.1*cos 28.8°= - 40.4 N

Fnx = 13.48 N- 40.4 N= -26.92 N

b) What is the y component of the net force acting on the object?

Fny= F₁y+ F₂y

F₁y= 33.4*cos 23.8° =30.6 N

F₂y= - 46.1*sin 28.8°= -22.2 N

Fny=30.6 N-22.2 N = 8.4 N

c) What is the x component of the equilibrant?

Fex: component of the equilibrant

Fex = - Fnx

Fex = - ( -26.92 N)

Fex = 26.92 N

d) What is the y component of the equilibrant?

Fey = - Fnx

Fey = - ( 8.4 N)

Fey = - 8.4 N

e) What is the magnitude of the equilibrant?

$F_{e}$ : equilibrant force

$F_{e} = \sqrt{(F_{e}x)^{2}+{(F_{e}y)^{2} }$

$F_{e} = \sqrt{(26.92)^{2}+{(-8.4)^{2} }$

$F_{e} = 28.2 N$

f) What is the angle the equilibrant makes with the x axis?

$\beta =tan^{-1} (\frac{-8.94}{26.96} )$

β = -18.34° or β = 18.34° clockwise from the positive x axis

5 0

3 years ago

What would happen if the moon were twice as big

IgorLugansk [536]

The universal gravity formula is F = G(Me)(Mm)/r^2. Lets use this formula to help us calculate what would happen if the Moon was twice as big.
Mn = new mass = 2*Mm
Fn = G(Me)(Mn)/r^2
Fn = G(Me)(2Mm)/r^2
Fn = 2*G(Me)(Mm)/r^2
Fn = 2*F
So 2 times the force it was before. The force should be the same, but you never know the moon and space as well know it can work in very mysterious ways.

7 0

3 years ago

Read 2 more answers