1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guajiro [1.7K]
3 years ago
14

A major motor company displays a die-cast model of its first automobile, made from 6.66 kg of iron. To celebrate its one-hundred

th year in business, a worker will recast the model in gold from the original dies. What mass of gold is needed to make the new model? Use Table 9.3 in the book for the data needed to solve this problem. Give your answer in SI units and to the correct significant figure.
Physics
1 answer:
luda_lava [24]3 years ago
4 0

Explanation:

According to table,

  Mass of iron model (m_{1}) is given as 6.66 kg

   Density of gold, (D_{2}) = 19320 kg/m^{3} unit

   Density of iron, (D_{1}) = 7850 kg/m^{3} unit

Now, new model shape = old model shape

So, volume or iron model = volume of gold model

That is,        V_{2} = V_{1}

As relation between density and volume is as follows.

               Volume = \frac{mass}{density}

Therefore,

         \frac{m_{2}}{D_{2}} = \frac{m_{1}}{D_{1}}

or,          m_{2} = D_{2} \times \frac{m_{1}}{D_{1}}

            m_{2} = 19320 \times \frac{6.66}{7850}

             m_{2} = 16.4 kg

Thus, we can conclude that mass of gold model, m_{2} is 16.4 kg.

You might be interested in
Atoms in a solid are not stationary, but vibrate about their equilibrium positions. Typically, the frequency of vibration is abo
hoa [83]

To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.

Our values are given as

f = 4.11 *10^{12} Hz

A = 1.23 * 10^{-11}m

The angular velocity of a body can be described as a function of frequency as

\omega = 2\pi f

\omega = 2\pi 4.11 *10^{12}

\omega=2.582*10^{13} rad/s

PART A) The expression for the maximum angular velocity is given by the amplitude so that

V = A\omega

V =( 1.23 * 10^{-11})(2.582*10^{13})

V =  = 317.586m/s

PART B) The maximum acceleration on your part would be given by the expression

a = A \omega^2

a =( 1.23 * 10^{-11})(2.582*10^{13})^2

a= 8.2*10^{15}m/s^2

4 0
3 years ago
A 5.09 × 1014-hertz electromagnetic wave is traveling through a transparent medium. The main factor that determines the speed of
sergiy2304 [10]
We are given an electromagnetic wave with a frequency of 5.09 x 10^14 Hz and travelling through a transparent medium. If the medium was vacuum, the speed of the wave would be equal to the speed of light. Otherwise, the main factor that would determine the speed of the wave is its wavelength.
6 0
3 years ago
Why does data need to be reliable
Karolina [17]
So results can be shared and used by other scientists that want to use or replicate your experiment.
8 0
3 years ago
Read 2 more answers
P6: An object of mass m sits on a spring of constant k in an elevator that is accelerating upwards with acceleration a. a) In te
tankabanditka [31]

Answer:

(a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

Explanation:

Given that,

Acceleration = a

mass = m

spring constant = k

(a). We need to calculate the spring compressed

Using balance equation

kx-mg=ma

x=\dfrac{ma+mg}{k}....(I)

The spring compressed is \dfrac{ma+mg}{k}.

(b). If the compression is 2.5 times larger than it is when the mass sits in a still elevator,

The compression is given by

x=2.5\times x_{0}

Here, acceleration is zero

So, x=2.5\times\dfrac{mg}{k}

We need to calculate the acceleration

Put the value of x in equation (I)

2.5\times \dfrac{mg}{k}=\dfrac{ma+mg}{k}

2.5\times\dfrac{mg}{k}=\dfrac{m}{k}(a+g)

a=2.5g-g

a=1.5g

Hence, (a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

8 0
3 years ago
Extend your thinking: household appliances are usually connected in a parallel circuit. why do you think it might be a problem i
alexandr1967 [171]
The equivalent resistance of several devices connected in parallel is given by
\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n}
where R_i are the resistances of the various devices. We can see that every time we add a new device in parallel, the term \frac{1}{R_{eq}} increases, therefore the equivalent resistance of the circuit R_{eq} decreases.

But Ohm's law:
I= \frac{V}{R_{eq}}
tells us that if the equivalent resistance decreases, the total current in the circuit increases. The power dissipated through the circuit (and so, the heat produced) depends on the square of the current:
P=I^2 R
therefore if there are too many devices connected in parallel, this can be a problem because there could be too much power dissipated (and too much heat) through the circuit.
6 0
3 years ago
Other questions:
  • What is the answer???
    11·1 answer
  • What is the displacement of an object that moves from the origin to a position at −12 m?
    14·2 answers
  • A student leaves a sidewalk corner walks 3.0 blocks north then walks 3.0 blocks west.what is the students displacement from the
    8·1 answer
  • At 8:00 am, the temperature in the earth science room was measured to be 62 degrees Fahrenheit. By 12:00 pm, the temperature had
    7·1 answer
  • How do objects and substances in motion have kinetic energy
    11·1 answer
  • 2.
    10·1 answer
  • Stars originate as large bodies of slowly rotating gas.Because of gravity, these clumps of gas slowly decrease in size.The angul
    6·1 answer
  • Which equation will tell you the acceleration of the object?
    10·1 answer
  • An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the pos
    7·1 answer
  • Am object of mass in a circular path of radius 100metres with the speed of 10metres/second.calculate the acceleration towards th
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!