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Fudgin [204]
3 years ago
15

How tall in cm is 5.4 feet

Physics
1 answer:
Digiron [165]3 years ago
3 0
That is 164.592cm = 5.4 feet
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the gas in a balloon has P=100000 pa and v=0.0279 m^3. if the pressure increases to 120000 pa at constant temperature, what is t
mash [69]

Answer:

New volume of the baloon is 0.02325m^3

Explanation:

To answer this question we need to know the ideal gas law, which says:

p•V = n•R•T

p is pressure, V is volume, n is amount of substance (in moles), R is constant value and T is temperature.

Since it's stated that n and T are constant, and we know that R is a constant too, that means that p•V = constant value. Basically, that means that p1•V1 (pressure and volume before the pressure increase) equals to p2•V2 (pressure and volume after the pressure increase).

That means that:

100000 Pa • 0.0279 m^3 = 120000 Pa • V2. Next, V2= 100000•0.0279/120000. So, V2=0.02325m^3.

6 0
3 years ago
Read 2 more answers
Two bodies of specific heats S1 and S2 having the same heat capacities are combined to form a single composite body. What is the
Dafna11 [192]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Heat capacity of body 1 :

\qquad \sf  \dashrightarrow \:m_1s_1

Heat capacity of body 2 :

\qquad \sf  \dashrightarrow \:m_2s_2

it's given that, the the head capacities of both the objects are equal. I.e

\qquad \sf  \dashrightarrow \:m_1s_1 = m_2s_2

\qquad \sf  \dashrightarrow \:m_1 =  \dfrac{m_2s_2}{s_1}

Now, consider specific heat of composite body be s'

According to given relation :

\qquad \sf  \dashrightarrow \:(m_1 + m_2) s' = m_1s_1 + m_2s_2

\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_1s_1 + m_2s_2}{m_1 + m_2}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ m_2s_2+ m_2s_2}{ \frac{m_2s_2}{s_1} + m_2 }

[ since, m_2s_2 = m_1s_1 ]

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2m_2s_2}{ m_2(\frac{s_2}{s_1} + 1)}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 \cancel{m_2}s_2}{  \cancel{m_2}(\frac{s_2}{s_1} + 1)}

\qquad \sf  \dashrightarrow \:s' = \dfrac{ 2 s_2}{  (\frac{s_2 + s_1}{s_1} )}

\qquad \sf  \dashrightarrow \: s' =  \dfrac{2s_1s_2}{s_1 + s_2}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

6 0
2 years ago
Read 2 more answers
If the mass is 2.0 kg and the acceleration is 5 m/s/s, then what is the force?
pshichka [43]

Answer:

Explanation:

F = ma = 2.0(5) = 10 N

5 0
2 years ago
Let r = .07 be the reserve rate. Which of the following is the money multiplier?
Ivanshal [37]
The formula for the money multiplier is :

1/ Reserve rate

so, the answer would be :

1/0.07
6 0
3 years ago
Read 2 more answers
Putting a beaker of water in a microwave and turning it on for a minute or two will increase the temperature of the water. Descr
Jobisdone [24]

Answer:

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made

Explanation:

The design of an experiment is to place the beaker in the microwave, with a good amount of water (approximately ⅔ of its capacity) and turn it on for small periods of time, generally the minimum is 30 s, quickly open the microwave, place a thermometer or better yet an infrared thermometer to measure the temperature of the water; repeat this several times.

The advantage of the infrared thermometer is that it reduces the transfer of heat between the water and the thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made.

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The main precaution that must be taken is not to open the microwave while it is on.

4 0
3 years ago
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