Answer:
(C). The line integral of the magnetic field around a closed loop
Explanation:
Faraday's law states that induced emf is directly proportional to the time rate of change of magnetic flux.
This can be written mathematically as;
is the rate of change of the magnetic flux through a surface bounded by the loop.
ΔФ = BA
where;
ΔФ is change in flux
B is the magnetic field
A is the area of the loop
Thus, according to Faraday's law of electric generators
∫BdL = 
= EMF
Therefore, the line integral of the magnetic field around a closed loop is equal to the negative of the rate of change of the magnetic flux through the area enclosed by the loop.
The correct option is "C"
(C). The line integral of the magnetic field around a closed loop
A. B. D. C. D, A, A, C, B, B, D, D
Answer:
The component form will be;
In the x-axis = 121.73 due west
In the y-axis = 690.35 due south
Explanation:
An image of the calculation has been attached
Answer: The angle of inclination is nearly 30°
Explanation:
For a body on an inclined plane, the coefficient of friction between the body and the plane is equal to the ratio of the moving force applied to the body to the frictional force acting on the body.
If uK coefficient of friction;
Fm is the moving force
R is the normal reaction on the body
Mathematically uK = Fm/R
Fm = WSin(theta)
R = Wcos(theta)
uK = Wsin(theta)/Wcos(theta)
uK = tan(theta)
theta = arctan(uK)
If uK is 0.58
theta = arctan0.58
theta = 30°
The angle of the inclined will be 30°
Answer
given,
radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m
mass of electron, M = 9.11 x 10⁻³¹ Kg
charge of electron, q₁ = 1.6 x 10⁻¹⁹ C
q₂ = 1.6 x 10⁻¹⁹ C
we know, force between two charges
F = 8.20 x 10⁻⁸ N
b) using newton's second law
F = m a
m a = 8.20 x 10⁻⁸
a = 9 x 10²² m/s²
c) speed of the electron
v² = 4.77 x 10¹²
v = 2.18 x 10⁶ m/s
d) the period of the circular motion.
T = 1.53 x 10⁻¹⁶ s
