Question

Jerry knocks a flowerpot off its third-story ledge, 9.5 m above the ground. If it falls freely, how fast is the flowerpot moving when it crashes to the sidewalk?

Answer 1

Answer:

13.65 m/s

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement = 9.5 m

a = Acceleration = 9.81 m/s²

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as-u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 9.5-0^2}\\\Rightarrow v=13.65\ m/s$

The flower pot is moving at a speed of 13.65 m/s when it crashes the sidewalk.