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oksian1 [2.3K]
3 years ago
12

Jerry knocks a flowerpot off its third-story ledge, 9.5 m above the ground. If it falls freely, how fast is the flowerpot moving

when it crashes to the sidewalk?
Physics
1 answer:
Veronika [31]3 years ago
3 0

Answer:

13.65 m/s

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement = 9.5 m

a = Acceleration = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as-u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 9.5-0^2}\\\Rightarrow v=13.65\ m/s

The flower pot is moving at a speed of 13.65 m/s when it crashes the sidewalk.

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Jonathan is riding a bicycle and encounters a hill of height 7.30 m. At the base of the hill, he is traveling at 6.00 m/s . When
Burka [1]

W= mgh + 0.5m*vf^2- 0.5m*vi^2.

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How much work does Jonathan do on the bicycle pedals within the Jonathan-bicycle-Earth system during this process?W= mgh + 0.5m*vf^2- 0.5m*vi^2

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6 0
2 years ago
A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren is 500 Hz
wariber [46]

Answer:

change in frequency is 636 Hz

Explanation:

given data

speed v1 = 36 m/s

speed v2 = 45 m/s

frequency f = 500 Hz

speed of sound s = 343 m/s

to find out

what is the change in frequency

solution

we know here change of frequency formula that is

frequency = \frac{s+v1}{s+v2} (f)   ...................1

put here value in equation 1

and we take v2 = -45 because opposite direction

frequency = \frac{s+v1}{s-v2} (f)

frequency = \frac{343+36}{343-45} (500)

frequency = 636

so change in frequency is 636 Hz

8 0
4 years ago
Crystallization of solids​
Deffense [45]

Answer:

A separation technique to separate solids from a solution. Crystallization can be defined as the process through which the atoms/molecules of a substance arrange themselves in a well-defined three-dimensional lattice and consequently, minimize the overall energy of the system.

Explanation:

3 0
3 years ago
Read 2 more answers
Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 2.33 m away from a waterfall 0.488 m in heigh
Ulleksa [173]

Answer:

5.68 m/s

Explanation:

The motion of the salmon is the same as a projectile: it is launched with an initial speed u at an angle of \theta=38^{\circ} above the horizontal.

The motion of the salmon consists of two indipendent motion:

- Along the horizontal direction, it is a uniform motion with constant velocity

v_x = u cos \theta

So that the distance travelled is

d=v_x t = u cos \theta t (1)

- Along the vertical direction, it is a uniformly accelerated motion with constant acceleration downward, so the vertical displacement is

y = u sin \theta t - \frac{1}{2}gt^2 (2)

where g is the acceleration of gravity.

We know the following:

- The horizontal distance travelled by the salmon to reach the waterfall is

d = 2.33 m

- The vertical distance travelled is the height of the waterfall,

y = 0.488 m

From (1) we get:

t=\frac{d}{u cos \theta}

And substituting into (2), we can solve the equation to find t, the time at which the salmon reaches the waterfall:

y = u sin \theta \frac{d}{u cos \theta} - \frac{1}{2}gt^2 = d tan \theta - \frac{1}{2}gt^2\\t = \sqrt{\frac{2(d tan \theta - y)}{g}}=\sqrt{\frac{2(2.33 tan 38^{\circ}-0.488)}{9.81}}=0.521 s

And then, we can use eq.(1) again to find the initial speed, u:

u=\frac{d}{cos \theta t}=\frac{2.33}{cos(38^{\circ})(0.521)}=5.68 m/s

5 0
3 years ago
Which picture correctly shows the path of the reflected light rays given an object outside the focal point?Select one:a. Ab. Bc.
nignag [31]

We will have that the graph that describes the scenario is given by graph B.

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