A I believe it would be true
Answer:
Explanation:
Let the tension in the string be T . At the top of the circle , total force acting on them = T + mg . This will provide centripetal force
T + mg = m v² / r
4 + .25 x 9.8 = .25 x v² / .62
6.45 = .25 v² / .62
v² = 16
v = 4 m /s .
The number of protons
number of neutrons=the mass number- number of protons
14-6=8
The density of the nickel was greater than that of the quarter and penny, thus, the results supports the hypothesis.
<h3>What is density of substance?</h3>
The density of a substance is a measure of how tightly-packed the particles of the substance are.
Density is calculated as the ratio of the mass of the substance and the volume of the substance.
The hypothesis of the lab to compare the densities of a penny, a nickel, and a quarter is:
- If the nickel has a greater density than the quarter and penny, then it will have a greater mass to volume ratio. If the nickel has a lower density than the quarter and penny, then it will have a lower mass-to-volume ratio.
The average mass and the average volume of a penny, a nickel, and a quarter are then used to determine the density of each coin.
Based on obtained results, it would be found that the density of the nickel was greater than that of the quarter and penny. Therefore, the results supports the hypothesis.
In conclusion, the density of a substance depends on the mass and the volume.
Learn more about density at: brainly.com/question/1354972
#SPJ1
Answer:
Cell Death
Explanation:
Cell death is defined as the biological process which ceases the function of the cell to carry out. This can be caused due to the formation of new cells in place of old cells.
Or it can be cause due to some serious disease or may be caused due to the injury or due to the death of that organism to which these cells belong.
And another case is that when X-ray photon interact with the human cell while it passes through the cell, it will damage the cell and cease it to function well and a more drastic condition occurs and that cell become dead.