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Sergeu [11.5K]
3 years ago
5

Which of the following best describes the internal layering of Jupiter, from the center outward?A) Core of rock and metal; mantl

e of lower density rock; upper layer of gaseous hydrogen; cloud layerB) Solid rock core; layer of solid metallic hydrogen; layer of pure liquid hydrogen; cloud layer.C) Liquid core of hydrogen compounds; liquid hydrogen layer; metallic hydrogen layer; gaseous hydrogen layer; cloud layer.D) Core of rock, metal, and hydrogen compounds; thick layer of metallic hydrogen; layer of liquid hydrogen; layer of gaseous hydrogen; cloud layer
Physics
1 answer:
statuscvo [17]3 years ago
8 0

Answer:

Option D

Explanation:

Jupiter is made almost totally from hydrogen and some hydrogen compounds. It may have a solid hydrogen core, then a liquid hydrogen layer, then a gaseous layer.  

It is not known if Jupiter has a solid surface, or even a liquid surface. We measure Jupiter's diameter from the top of its gas layer.

The core is often described as rocky, but its detailed composition is unknown, as are the properties of materials at the temperatures and pressures.

The presence of a core during at least part of Jupiter's history is suggested by models of planetary formation that require the formation of a rocky or icy core massive enough to collect its bulk of hydrogen and helium from the protosolar nebula. Assuming it did exist, it may have shrunk as convection currents of hot liquid metallic hydrogen mixed with the molten core and carried its contents to higher levels in the planetary interior. A core may now be entirely absent, as gravitational measurements are not yet precise enough to rule that possibility out entirely.

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In 1 km races, runner 1 on track 1 (with time 2 min, 28.13 s) appears to be faster than runner 2 on track 2 (2 min, 28.48 s). ho
Murrr4er [49]
We are given with a velocity-distance-time kinematic problem given the different times of two runners and is asked for the difference in distances the runner has ran in the track. we use the formula v= d/t where d is the distance of running, t is time and v is the velocity of the runner. 

First runner, 
v = d/t = 1000 m / (120+28.13s ) = 6.750826976 m/s
Second runner
Using the same velocity we determine d2.
v = d2/t2 = d2 / (120+28.48s) = 6.750826976 m/s ; d2 = 1002.362789

distance of running track is the difference of the two distance achieved by the runners, delta d= d2 - d = 2.362789 m 
3 0
3 years ago
A light spring of constant 179 N/m rests vertically on the bottom of a large beaker of water. A 5.32 kg block of wood of density
Digiron [165]

Answer:

Compression of the spring: 0.18 m (downward)

Explanation:

The forces acting on the block of wood are:

- The force of gravity, acting downward, of magnitude mg, where m = 5.32 kg is the mass of the block and g=9.8 m/s^2 is the acceleration due to gravity

- The force exerted by the spring, downward, of magnitude kx, where k=179N/m is the spring constant and x is the elongation of the spring

- The buoyant force, upward, of magnitude \rho V g, where \rho=1000 kg/m^3 is the water density and V the volume of the block

Since the block is in equilibrium, the net force is zero, so we can write

mg+kx-\rho V g=0 (1)

We have to find the volume of the block first. We have:

m = 5.32 kg (mass)

\rho_w = 622 kg/m^3 (wood density)

So, the volume is

V=\frac{m}{\rho_w}=\frac{5.32}{622}=0.0086 m^3

So now we can re-arrange eq.(1) to find the elongation of the spring, x:

x=\frac{-mg+\rho Vg}{k}=\frac{-(5.32)(9.8)+(1000)(0.0086)(9.8)}{179}=0.18 m

So, the spring is compressed by 0.18 m.

7 0
3 years ago
Particles of charge +75, +48, and -85μC are placed in a line. The center one is 0.35 m from each of the others. Calculate the ne
ikadub [295]
+X axis is passing through from +75 to +48. then to _83
Now force on +75 due to +48 is being repulsive, with the direction -X, So the X component of force is negative.
Force on +75 due to -85 is attractive, with the direction of +X.
∴ The X component of force is positive
K is always constant and positive.
4 0
4 years ago
A circular solenoid of radius R = 2cm passes through a square loop of wire with 1 turn and sides of length ℓ = 5cm. The solenoid
ankoles [38]
The answer for this problem is D
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4 years ago
An eartly method of measuring the speed of light makes use of a rotating slotted wheel.
Pavel [41]

Answer:

Explanation:

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time taken by light to travel this distance = 1100 / 3 x 10⁸

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= ω R , r is radius of wheel , ω is angular velocity.

= 1091π x 5 x 10⁻²

= 1712.8 m /s

4 0
4 years ago
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