Question

A crate is pulled to the right with a force of 85 N, to the left with a force of 115 N, upward with a force of 565 N, and downward with a force of 236 N.
1. Find the magnitude and direction of the net external force on the crate.

Answer 1

Answer:

330.4 N and  $95.2^{\circ}$counterclocwise to the x direction

Explanation:

Sum of forces in vertical are equal, let movement to right and upwards be positive while left and downwards be negative

Net force in horizontal direction is 85-115=-30 N

Net force in vertical direction is 565-236=329 N

Resultant force=$\sqrt {(-30)^{2}+329^{2}}=330.3649497 N\approx 330.4 N$

Direction=$tan^{-1}\frac {329}{-30}=-84.78986932\approx -84.8^{\circ}$

180-84.8=95.2

Therefore, direction is $95.2^{\circ}$counterclocwise to the x direction