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Lyrx [107]
3 years ago
8

Given the following balanced reaction: 2 NH3 +CO2 --> CH4N2O + H2O A reaction produces 87.5g of CH4N2O upon the reaction of 6

8.2g of NH3 with 105 g of CO2. (a) determine the limiting reagent. (b) Theoretical yield of CH4N2O (c) percent yield of the reaction (d) show full work and explain in your own words how you solved this problem.
(a,b,c,d are all different parts to the question)
Chemistry
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

ml lang yan pre tara laro

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Nuetrik [128]
C=3.0 mol/L
n=1.50 mol

n=cv

v=n/c

v=1.50/3.0=0.5 L = 500 mL

6 0
3 years ago
Which is not true of the element nitrogen?
insens350 [35]
B is the answer or check it out
6 0
3 years ago
The molarity of a sodium hydroxide (NaOH) solution is 0.2 M. The molar mass of NaOH is 40 g/mol. If the solution contains 20 g o
mote1985 [20]

Answer:

\large \boxed{\text{2.5 L}}

Explanation:

1. Calculate the moles of NaOH.

\text{Moles} = \text{20 g} \times \dfrac{\text{1 mol}}{\text{40 g}} = \text{0.50 mol}

2. Calculate the volume of NaOH

\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is $\large \boxed{\textbf{2.5 L}}$}

7 0
3 years ago
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sp2606 [1]

Answer:19. He says that he’s been really tired since several weeks ago. 20. A friend of us is going to pick us up at the airport. 21. I’ve worked like a waiter in the past, but I wouldn’t want to do it again. 22

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7 0
2 years ago
What is the mass of 2.9 moles of calcium? Explain please
Alik [6]

Answer:

116 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of calcium = 2.9 moles

Mass of calcium =.?

The mole and mass of a substance are related according to the following formula:

Mole = mass / molar mass

With the above formula, we can obtain the mass of calcium. This can be obtained as follow:

Number of mole of calcium = 2.9 moles

Molar mass of calcium = 40 g/mol

Mass of calcium =.?

Mole = mass / molar mass

2.9 = mass of calcium / 40

Cross multiply

Mass of calcium = 2.9 × 40

Mass of calcium = 116 g

Therefore, the mass of 2.9 moles of calcium is 116 g.

4 0
3 years ago
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