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Gnoma [55]
3 years ago
9

HELPPPPPPPPPPPPP??????

Physics
2 answers:
zhuklara [117]3 years ago
7 0

Answer:

The picture is not clear

lyudmila [28]3 years ago
6 0

Answer:

Displacement is 0

Explanation:

This is for first question

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(a) Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and
notsponge [240]

Answer:

(a) The Work need to   place spacecraft into low orbit isGmm_{E} /2R_{E}

(b) Additional Work need to  place the spacecraft far away from the earth is

Gmm_{E} /2R_{E}.

(c) From part(a) and part(b) we observe the Both quantities are equal.

Explanation:

Explanation is in the following attachments

8 0
3 years ago
Why doesn’t the total pressure increase when more gas is added to the chamber? (hint: what would you see if the volume of the ch
dem82 [27]

Answer:

It won't increase according to Boyle's law

Explanation:

Volume of a gas varies inversely as the pressure so as more fixed volume of gas is added to the chamber the pressure reduces

5 0
2 years ago
What is a continuous range of a single feature such as a wave lengt
Evgen [1.6K]

<span>I think you're looking for "spectrum".</span>



7 0
3 years ago
What is the ideal mechanical advantage of a lift that allows you raise a 90.0-kg refrigerator with 80.0 N of force?
Sholpan [36]

Answer:

11

Explanation:

5 0
3 years ago
10. A 25 kg apple cart is being pushed with an applied force of 115 N. The coefficient of friction between the ground and the ca
ziro4ka [17]

Answer:

1.1 m/s²

Explanation:

From the question,

F -mgμ = ma.................... Equation 1

Where F = applied force, m = mass of the apple cart, g = acceleration due to gravity, μ =  coefficient of friction., a = acceleration of the apple cart.

Given: F = 115 N, m = 25 kg,  μ  = 0.35

Constant: g = 10 m/s²

Substitute these values into equation 2

115-(25×10×0.35) = 25×a

115-87.5 = 25a

25a = 27.5

a = 27.5/25

a = 1.1 m/s²

8 0
3 years ago
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