If the forces are equal, at a distance equidistant it is not possible to act a pair on the body since both torques cancel each other. Being of the same magnitude and in the opposite direction, the sum of the torques will be zero.
Answer:
Hey guys...I Miss you very much.I wish i could come home.But i have a mission to complete and i have to complete it. Tell the kids i said hi and i live them very much
Explanation:
GREETING: Hey family i miss you all very much i hope you guys are ready for me to come home.
Answer:
a) E = 1.06 10⁻¹⁹ J, b) v = 9.78 10⁵ m / s
Explanation:
The physical magnitudes can be given in several units, but in general all must be reduced to the same system in a given exercise, the most used system is the international (SI)
1 eV =q V= 1.6 10⁻¹⁹ J
let's reduce the quantities requested
a) E = 1.0 eV to Joule
E = 1.0 eV (1.6 10⁻¹⁹ J / 1 eV)
E = 1.06 10⁻¹⁹ J
b) the kinetic energy is given by
K = ½ m v²
v = 
the mass of the proton is
m = 1,673 10⁻²⁷ kg
let's reduce the energy to the SI system
E = 5000 ev (1.6 10-19 J / 1 eV) = 8000 10⁻¹⁹ J
let's calculate
v =
v =
v = 9.78 10⁵ m / s
Answer:735.46N, 626.34N
Explanation: when an elevator ascend, it means it moving against gravity
F= m(a+g)
M=66kg
a=v/t
g=9.81m/s^2
For the first a= 1.2/0.9
a=1.2/0.9
a=1.33m/s2
F=66(1.33+9.81)
F=66(11.143)
F=735.46N
F=m(a+g)
a=v/t
a=-1.6/5
a=-0.32m/s2
F=66(-0.32+9.8)
F=66(9.49)
F=626.34N