You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it de
1 answer:
The age of the given rock is 700 million years.
The given parameters;
- <em>original mass of the rock, = 20 g</em>
- <em>mass of the rock remaining after decay, = 10 g</em>
- <em>half life of Uranium, </em>
<em> = 700 years</em>
age of the rock ----------------------------- mass remaining
0 ------------------------------------------- 20 g
1 half life ( ) ------------------------------ 10 g
Age of the rock
Thus, the age of the given rock is 700 million years.
Learn more here:brainly.com/question/23774743
You might be interested in
The correct answer to the question is : 29.88 m.
EXPLANATION :
As per the question, the mass of the rock m = 50 Kg.
The rock is rolling off the edges of the cliff.
The final velocity of the rock when it hits the ground v = 24 .2 m/s.
Let the height of the cliff is h.
The potential energy gained by the rock at the top of the cliff = mgh.
Here, g is known as acceleration due to gravity, and g =
When the rock rolls off the edge of the cliff, the potential energy is converted into kinetic energy.
When the rock hits the ground, whole of its potential energy is converted into its kinetic energy.
The kinetic energy of the rock when it touches the ground is given as -
Kinetic energy K.E = .
From above we know that -
Kinetic energy at the bottom of the cliff = potential energy at a height h
⇒
⇒
⇒
⇒
Hence, the height of the cliff is 29.88 m
Answer:
the force of attraction between the two charges is 3.55 N.
Explanation:
Given;
first charge carried by the object, q₁ = 15.5 µC
second charge carried by the q₂ = -7.25 µC
distance between the two charges, r = 0.525 m
The force of attraction between the two charges is calculated as;
Therefore, the force of attraction between the two charges is 3.55 N.