Answer:
non linear square relationship
Explanation:
formula for centripetal force is given as
a = mv^2/r
here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have
a = constant × v^2
a α v^2
hence non linear square relationship
Answer:
Janet jumps off a high diving platform with a horizontal velocity of 2.89 m per s and lands in the water 1.5 s later. How high is the platform?
Platform is 11.025 meters high .
Explanation:
we have Vx = 2.89 m/s
time taken = 1.5 seconds
height of the platform = ?
so,
As Janet is jumping from a high diving platform from a certain unknown height their must be involvement of gravity in action.
we can use,
h = Vi*t+(1/2)*g*t^2
where ,
h = height
Vi = initial horizontal velocity that will be zero
t = time in seconds
g = gravity due to acceleration
now put the values
h = 0+(1/2)*(9.8)*(1.5)^2
h = 11.025-m
Answer:
C
Explanation:
- Let acceleration due to gravity @ massive planet be a = 30 m/s^2
- Let acceleration due to gravity @ earth be g = 30 m/s^2
Solution:
- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:
t = v / a
t = v / 30
- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:
t = v / g
t = v / 9.81
- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C
