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lilavasa [31]
4 years ago
9

A spring balance used to weigh candy is built with a spring the spring stretches 3.00 cm when a 15 n weight is placed in the pan

. when the weight is replaced with 3 kg of candy, what distance will the spring stretch?
a.7.0 b.4.5 c.3.8 d.5.9
Physics
1 answer:
ira [324]4 years ago
6 0

Answer: 5.9cm

Explanation:

15N/3cm=5

Convert 3kg to N (29.42N)

Use the 5 from earlier to divide 29.42/5=5.884

Round to 5.9

5.9cm is the answer

(I don’t know if I solved this the correct way but I got it right. 5.9 is the correct answer)

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i need help please. this is for physics but everything i search for related to this comes up as chemistry
Annette [7]

The car tyre contains air initially at a pressure of 195 kPa after travelling several km the temperature of the air inside a car tyre rises from 30 to 70°C if the tyre is rigid and does not expand then the new pressure inside the tyre would be 220.74 kPa.

<h3>What is pressure?</h3>

The total applied force per unit of area is known as the pressure.

The pressure depends both on externally applied force as well the area on which it is applied.

The mathematical expression for the pressure

Pressure = Force /Area

the pressure is expressed by the unit pascal or N /m²

By using the Charles law for gases which states that the volume of the gas remains constant then the pressure of the gas is directly proportional to the temperature.

As given in the problem the tyre is rigid and does not expand this means the volume of the tyre remains constant.

The mathematical expression for Charles's law is as follows

P₁/P₂ = T₁/T₂

First, we have to change the temperature from degree Celcius to the kelvin temperature scale

K = 273 + C

where k is the temperature in kelvin and the C is degrees of Celcius

Initially, the temperature was 30° C

T₁ = 273 + 30

T₁ = 303 K

Then after travelling the temperature of the air inside a car tyre rises from 30 to 70°C

T₂= 273+ 70

T₂ =343 K

The car tyre contains air initially at a pressure of 195 KPa

P₁ = 195 kPa

Lets us take the final pressure of the air would be P₂

By substituting the values in the formula

P₁/P₂ = T₁/T₂

195/P₂ = 303/343

P₂ = 220.74 kPa

Thus, the new pressure inside the tyre would be  220.74 kPa.

Learn more about pressure learn more

brainly.com/question/28012687

#SPJ1

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2 years ago
A ray diagram shows that an object is placed between the focal point and the vertex of a convex mirror. What are the characteris
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The correct answer is: <span>smaller than object, virtual and upright.
</span>
When the object is placed between the focal point and the vertex of a convex mirror, then the image formed will be <span>located behind the convex mirror. It will be virtual image and an upright image but reduced in size (i.e., smaller than the object)</span>

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4 years ago
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What happens to an electromagnetic wave as it passes from space to matter?
alina1380 [7]

Answer:

When an electromagnetic wave passes from space to matter, some part of the energy is absorbed by the matter and it increases its energy. The wave may reflect and some part may pass through the matter depending on the amount of energy they have. The amplitude of the wave decreases if some parts of it are reflected.

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3 years ago
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Answer:

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3 years ago
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Helen [10]

The acceleration of the object if the net force is decreased = 0.13 m/s²

<h3>Further explanation</h3>

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

\tt \sum F=m.a

The mass used in state 1 and 2 remains the same, at 1.5 kg

  • state 1

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2

  • state 2

ΣF=0.2 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2

8 0
3 years ago
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