K5O2
convert grams to moles, divide both by the smallest mole mass, multiply that until hole.
30.5 g K ÷ 39.10 = .78 mol
6.24 g O ÷ 16 = .39 mol
.78 mol ÷ .39 mol = 2.5
.39 mol ÷ .39 mol = 1
2.5 x 2 = 5
1 x 2 = 2
K5O2
The first one is some reaction with water even I am studying the same
Answer:
I hope this helps you!
Explanation:
The retina is the back part of the eye that contains the cells that respond to light. These specialized cells are called photoreceptors. ... The rods are most sensitive to light and dark changes, shape and movement and contain only one type of light-sensitive pigment. Rods are not good for color vision.
Answer:

Explanation:
Hello,
In this case, for the given reaction:

In such a way, the initial concentrations are:
![[H_2]_0=\frac{1.30x10^{-2}mol}{0.1L}=0.130M](https://tex.z-dn.net/?f=%5BH_2%5D_0%3D%5Cfrac%7B1.30x10%5E%7B-2%7Dmol%7D%7B0.1L%7D%3D0.130M)
![[NO]_0=\frac{2.60x10^{-2}mol}{0.1L}=0.260M](https://tex.z-dn.net/?f=%5BNO%5D_0%3D%5Cfrac%7B2.60x10%5E%7B-2%7Dmol%7D%7B0.1L%7D%3D0.260M)
Thus, at equilibrium, the change
, due to the chemical reaction extent, turns out:
![x=\frac{[NO]_{0}-[NO]_{eq}}{2} =\frac{0.260M-0.161M}{2}=0.049M](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%5BNO%5D_%7B0%7D-%5BNO%5D_%7Beq%7D%7D%7B2%7D%20%3D%5Cfrac%7B0.260M-0.161M%7D%7B2%7D%3D0.049M)
Thus, the rest of the concentrations at equilibrium are:
![[H_2]_{eq}=0.130M-2(0.049M)=0.032M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D0.130M-2%280.049M%29%3D0.032M)
![[H_2O]_{eq}=2(0.049M)=0.098M](https://tex.z-dn.net/?f=%5BH_2O%5D_%7Beq%7D%3D2%280.049M%29%3D0.098M)
![[N_2]_{eq}=0.049M](https://tex.z-dn.net/?f=%5BN_2%5D_%7Beq%7D%3D0.049M)
In such a way, the equilibrium constant for the reaction, result as follows, even when on the statement the NO is excluded, because it participates in the equilibrium:
![Kc=\frac{[H_2O]_{eq}^2[N_2]_{eq}}{[H_2]_{eq}^2[NO]_{eq}^2}=\frac{(0.098M)^2(0.049M)}{(0.032M)^2(0.161M)^2} \\\\Kc=17.7](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2O%5D_%7Beq%7D%5E2%5BN_2%5D_%7Beq%7D%7D%7B%5BH_2%5D_%7Beq%7D%5E2%5BNO%5D_%7Beq%7D%5E2%7D%3D%5Cfrac%7B%280.098M%29%5E2%280.049M%29%7D%7B%280.032M%29%5E2%280.161M%29%5E2%7D%20%5C%5C%5C%5CKc%3D17.7)
Best regards.