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Andreyy89
2 years ago
14

Explain the relationship between the volume of a gas and it’s pressure.

Chemistry
1 answer:
Olin [163]2 years ago
8 0

Answer:

Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship, when temperature is held constant. If volume increases, then pressure decreases and vice versa, when temperature is held constant

Explanation:

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2 years ago
A 0.75mol calcium carbonate (CaCO3) pellet has what mass?
aleksandr82 [10.1K]

Answer:

75 g  

Step-by-step explanation:

<em>Step 1. </em>Calculate the molar mass of CaCO₃

Ca                    =   40.08

  C                    =   12.01

3O = 3 × 16.00 = <u>  48.00 </u>

               Total = 100.09 g/mol

<em>Step 2</em>. Calculate the mass of the pellet

Mass of CaCO₃ = 0.75 mol × (100.09 g/1 mol)

Mass of CaCO₃ = 75 g

4 0
2 years ago
At 250°C an equilibrium mixture of SbCl3(g), Cl2(g), and SbCl5(g) has the partial pressures 0.670 bar, 0.438 bar, and 0.228 bar,
Sveta_85 [38]

Explanation:

As the given reaction will be SbCl_{3}(g) + Cl_{2}(g) \rightarrow SbCl_{5}

Since, it is given that volume of reaction vessel is doubled. Hence, moles of species involved will also increase.

Therefore, the reaction equation will become as follows.

             2SbCl_{3}(g) + 2Cl_{2}(g) \rightarrow 2SbCl_{5}

As it is given that partial pressure of SbCl_{3} is 0.670 bar, Cl_{2} is 0.438 bar and SbCl_{5} is 0.228 bar.

Expression to calculate new equilibrium pressure if the volume of reaction vessel is double is as follows.

                  K_{p} = \frac{[P_{SbCl_{5}}]^{2}}{[P_{SbCl_{3}}]^{2}[P_{Cl_{2}}]^{2}}

                                   = \frac{(0.228)^{2}}{(0.670)^{2}(0.438)^{2}}

                                   = 6.05 \times 10^{3}

Thus, we can conclude that new equilibrium pressures if the volume of the reaction vessel is doubled is 6.05 \times 10^{3}.

4 0
3 years ago
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