Answer:
c
Explanation:
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Answer:
75 g
Step-by-step explanation:
<em>Step 1. </em>Calculate the molar mass of CaCO₃
Ca = 40.08
C = 12.01
3O = 3 × 16.00 = <u> 48.00
</u>
Total = 100.09 g/mol
<em>Step 2</em>. Calculate the mass of the pellet
Mass of CaCO₃ = 0.75 mol × (100.09 g/1 mol)
Mass of CaCO₃ = 75 g
Explanation:
As the given reaction will be 
Since, it is given that volume of reaction vessel is doubled. Hence, moles of species involved will also increase.
Therefore, the reaction equation will become as follows.

As it is given that partial pressure of
is 0.670 bar,
is 0.438 bar and
is 0.228 bar.
Expression to calculate new equilibrium pressure if the volume of reaction vessel is double is as follows.
![K_{p} = \frac{[P_{SbCl_{5}}]^{2}}{[P_{SbCl_{3}}]^{2}[P_{Cl_{2}}]^{2}}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BP_%7BSbCl_%7B5%7D%7D%5D%5E%7B2%7D%7D%7B%5BP_%7BSbCl_%7B3%7D%7D%5D%5E%7B2%7D%5BP_%7BCl_%7B2%7D%7D%5D%5E%7B2%7D%7D)
= 
= 
Thus, we can conclude that new equilibrium pressures if the volume of the reaction vessel is doubled is
.