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Leno4ka [110]
3 years ago
6

Consider a laser pointer that emits red light with wavelength 650 nm. This light is used for a photoelectric effect experiment w

here the anode in the evacuated glass tube is made up of a material that has work function equal to 1 eV. 1. What is the energy of an individual photon that comes out of the laser pointer?
Physics
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

<em>The energy of an individual photon that comes out of the laser pointer is 1.91 eV</em>

Explanation:

The energy of a photon can be obtained using the expression below

E = hc/λ

where E is the energy;

h is the Planck's constant  = 6.626 x 10-34 Js;

c is the speed of light = 3.00 x 10^{8} m/s (speed of light);

λ is the wavelength = 650 nm =650 x 10^{-9} m.

E = (6.626 x 10-34 Js) x (3.00 x 10^{8} m/s) /650 x 10^{-9} m

E = 3.058 x 10^{-19} J

1 joule = 6.242 x 10^{18} eV

3.058 x 10^{-19} J = 3.058 x 10^{-19} J x 6.242 x 10^{18} eV = 1.91 eV

Therefore the energy of an individual photon that comes out of the laser pointer is 1.91 eV

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