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yKpoI14uk [10]
2 years ago
13

Crude oil is ________. a. composed of less than ten different hydrocarbon molecules b. formed in a wide range of temperature and

pressure circumstances c. fractionated to separate the chemicals used for gasoline, lubricants, plastics and other products d. formed less than 100 yards below the surface; in deeper places with more pressure, coal is formed e. usable in its raw form
Chemistry
1 answer:
Arisa [49]2 years ago
3 0

Answer:

C

Explanation:

A - Crude oil is composed for hundreds of hydrocarbon, not less than ten.

B - Is formed in specific conditions of temperature and pressure

C - It's fractionated to form gasoline, lubricants, CH4, plastics and many other products made of hydrocarbon.

D - We have crude oil located more than 4000 yards below the surface in countries like Brazil

E - The crude oil is very thick and don't have an specific usage, so we need to refine it.

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In order to prepare 50.0 mL of 0.100 M NaOH you will add _____ mL of 1.00 M NaOH to _____ mL of water
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The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).

Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.

We can use the following equation to calculate the volume of more concentrated solution required:

\begin{gathered} C_1\times V_1=C_2\times V_2 \\ V_1=\frac{C_2\times V_2}{C_1} \end{gathered}

where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).

Applying the values given by the question to the equation above, we'll have:

\begin{gathered} V_1=\frac{C_2\times V_2}{C_1} \\ V_1=\frac{0.100M_{}\times50.0mL_{}}{1.00M_{}}=5.00mL \end{gathered}

Thus, we would need 5.00 mL of the more concentrated solution.

Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:

\begin{gathered} \text{final volume = volume of initial solution + volume of water} \\ 50.0mL=5.00mL\text{ + volume of water} \\ \text{volume of water = 45.0 mL} \end{gathered}

Thus, we would need 45.0 mL of water to prepare the solution.

Therefore, we can complete the sentence given as:

<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>

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10 months ago
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Answer:

                                                               

Explanation:

                                                                           

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