Answer:
x²+11x+28
Step-by-step explanation:
(f - g) (x) = f(x) - g(x)
x² + 12x + 32 - (x + 4) = x² + 11x + 28
Answer:
a. The probability that a customer purchase none of these items is 0.49
b. The probability that a customer purchase exactly 1 of these items would be of 0.28
Step-by-step explanation:
a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:
let A represents suit
B represents shirt
C represents tie
P(A) = 0.22
P(B) = 0.30
P(C) = 0.28
P(A∩B) = 0.11
P(C∩B) = 0.10
P(A∩C) = 0.14
P(A∩B∩C) = 0.06
Therefore, the probability that a customer purchase none of these items we would have to calculate the following:
1 - P(A∪B∪C)
P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)
= 0.22+0.28+0.30-0.11-0.10-0.14+0.06
= 0.51
Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49
The probability that a customer purchase none of these items is 0.49
b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:
= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2 P(A ∩ B ∩ C))
=0.51 -0.23 = 0.28
The probability that a customer purchase exactly 1 of these items would be of 0.28
Answer:number of cupcakes sold is 13
Number of cookies sold is 27
Step-by-step explanation:
Let x represent the number of cupcakes that Jane sold.
Let y represent the number of cookies that Jane sold.
Each cupcake sold for $2.25 and each cookie sold for $0.50. At the end of the day, Jean had sold $42.75 worth of cookies and cupcakes.
This means that
2.25x + 0.5y = 42.75 - - - - - - - - - -1
she sold 40 cupcakes and cookies combined, it means that
x + y = 40
Substituting x = 40 - y into equation 1, it becomes
2.25(40 - y) + 0.5y = 42.75
90 - 2.25y + 0.5y = 42.75
- 2.25y + 0.5y = 42.75 - 90
- 1.75y = - 47.25
y = - 47.35/-1.75
y = 27
x = 40 - y
x = 40-27 = 13
.
Answer:
110%
Step-by-step explanation:
just divide by 2
20/2 = 10
22/2 = 11
so x% of 10 = 11
1.10 just like the last problem
110%
Answer:
a = $13.5
Step-by-step explanation:
Let a = adult tickets
Let c = children tickets
Translating the word problem into an algebraic equation;
<u>For the Martinez family;</u>
2a + 3c = $60
<u>For the Wright family;</u>
3a + 5c = $95.5
Thus, the simultaneous equations are;
..........equation 1
.........equation 2
We would use substitution method to solve;
From equation 2, we make a the subject of formula;
3a = 95.5 - 5c
a = (95.5 - 5c)/3
<em>Substituting the value of "a" into equation 1, we have;</em>
2[(95.5-5c)/3] + 3c = 60
Multiplying all through by 3;
2(95.5 - 5c) + 9c = 180
191 - 10c + 9c = 180
191 - c = 180
c = 191-180
c = $11
To find the value of a;
2a +3c = 60
<em>Substituting the value of "c" into the equation, we have;</em>
a = $13.5
<em>Therefore, the cost of an adult movie ticket is $13.5. </em>
