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Reika [66]
3 years ago
7

The factor that affects how easily an electron can be removed from an atom is the.

Chemistry
1 answer:
zalisa [80]3 years ago
4 0
Atomic radius aka distance from the nucleus to the outermost energy level. The greater this distance, the less electrostatic attraction between these oppositely charged particles.
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What is the relationship between frequency and wavelength?
IrinaVladis [17]

Answer:

frequency it the measure of the wave length. The measure of the peaks and troughs is how you measure the frequency. the distance between these is the wave length.

6 0
2 years ago
A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
  • \Delta \epsilon = 25

Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

           =1.12\times 10^{-4}\times 12500

           =1.4  \ mL

8 0
3 years ago
Which of the following elements would be predicted to be the best conductor of electricity? sodium (Na) germanium (Ge) sulfur (S
lubasha [3.4K]
Na because its a metal. Metals are the best conductors. S and Ne are nonmetals. and Ge is a metalloid. (Metalloids are semi conductors)
4 0
3 years ago
Read 2 more answers
Methane burns in oxygen to produce carbon dioxide and water. Which of the following represents
Brut [27]

Answer:

A

Explanation:

CH4+O2-CO2+ H20

that mean methane has burn in oxygen to produce CO2

8 0
3 years ago
A piece of an unknown substance weighing 124.0 grams is heated in boiling water to 100.0oc. when the substance is placed in a ca
MakcuM [25]

The heat cause 300g water temperature increase from 20 to 26 celcius. The heat transferred would be: 300g * (26 °C -20 °C) *4.2 joule/gram °C= 7560J

The unknown substance is added to the water, so its final temperature should be the same as the water. The calculation would be:

7560J= 124g * (100-26)* specific heat

specific heat= 7560J / 124g / 74 °C= 0.8238 J/gram °C

3 0
3 years ago
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