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Harman [31]
3 years ago
9

A scientist adds iodine as an indicator to an unknown substance. What will this indicator reveal about the substance?

Chemistry
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

it will turn blue black to any substance

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Consider this equilibrium:
galben [10]
<span>This is the complete answer, including the set of answer choices:

Certain conditions provide less than 10% yield of NH3 at equilibrium. Which statement describes this equilibrium?

A. The Keq is large and products are favored.
B. The Keq is small and products are favored.
C. The Keq is large and reactants are favored.
D. The Keqis small and reactants are favored.
E. The conditions of the reaction must be known to answer the question


To answer you must know that the equilibrium yield is the quantity of product obtained.

In this case it is 10% of NH3.

That means that the equilibrium is more favorable to the reactants.

Given that Ke relates the concentration of products / concentration of reactants, the answer is the Ke is small and reactants are favored
</span>
7 0
4 years ago
Read 2 more answers
Lesson one review:
expeople1 [14]

Mixtures are impure substances composed of two or more substances physically combined.

<h3>What are mixtures?</h3>

Mixtures are substances that are composed of two or more substances physically combined.

Mixtures are one of the different types of substances which are composed of matter.

The classification of matter by type of substance is as follows:

  • Matter - Pure and impure substances or mixtures
  • Pure substances - elements and compounds
  • Mixtures: homogenous and heterogenous

In conclusion, substances can be classified into either pure substances or mixtures.

Learn more about  substances and mixtures at: brainly.com/question/1867365

#SPJ1

7 0
2 years ago
Pb(OH)Cl, one of the lead compounds used in ancient Egyptian cosmetics, was prepared from PbO according to the following recipe:
sladkih [1.3K]

Answer:

8.59 g

2.25 g

Explanation:

According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-

Moles of Pb(OH)CL is

= \frac{Mass}{Molar\ mass}

= \frac{10.0 g}{259.65g / mol}

= 0.0385 mol

Mass of PbO needed is

= 0.385mol Pb(OH) Cl\times \frac{1 mol PbO}{1molpb (OH) cl} \times \frac{223.2g PbO}{1mol PbO}

After solving the above equation we will get

= 8.59 g

Mass of NaCL needed is

= \frac{1mol\ NaCl}{1molPb\ (OH)Cl} \times \frac{58.45NaCl}{1mol NaCl}

After solving the above equation we will get

= 2.25 g

Therefore we have applied the above formula.

7 0
3 years ago
Steam reforming of methane ( CH4 ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the sta
Hatshy [7]

<u>Answer:</u> The pressure equilibrium constant for the reaction is 1473.8

<u>Explanation:</u>

We are given:

Initial partial pressure of methane gas = 2.4 atm

Initial partial pressure of water vapor = 3.9 atm

Equilibrium partial pressure of hydrogen gas = 6.5 atm

The chemical equation for the reaction of methane gas and water vapor follows:

                        CH_4+H_2O\rightleftharpoons CO+3H_2

<u>Initial:</u>               2.4       3.9

<u>At eqllm:</u>        2.4-x    3.9-x        x       3x

Evaluating the value of 'x':

\Rightarrow 3x=6.5\\\\x=2.167

So, equilibrium partial pressure of methane gas = (2.4 - x) = [2.4 - 2.167] = 0.233 atm

Equilibrium partial pressure of water vapor = (3.9 - x) = [3.9 - 2.167] = 1.733 atm

Equilibrium partial pressure of carbon monoxide gas = x = 2.167 atm

The expression of K_p for above equation follows:

K_p=\frac{p_{CO}\times (p_{H_2})^3}{p_{CH_4}\times p_{H_2O}}

Putting values in above equation, we get:

K_p=\frac{2.167\times (6.5)^3}{0.233\times 1.733}\\\\K_p=1473.8

Hence, the pressure equilibrium constant for the reaction is 1473.8

5 0
4 years ago
I WILL GIVE U BRAINLIEST
PtichkaEL [24]

Answer:

guidelines

Explanation:

It gives perameters for her abilities :)

7 0
3 years ago
Read 2 more answers
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