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r-ruslan [8.4K]
3 years ago
14

A 10 kg block slides on a frictionless surface at 10 m/s . It hits a rough patch 3 meters long with a coefficient of kinetic fri

ction of 0.4. When it reenters the frictionless surface , how fast is it going?
Physics
1 answer:
Valentin [98]3 years ago
8 0

12 MPH

I DIDNT do the math my brother did  hes in colledge so good lucks guys

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A spring stretches 5 cm when a 300-N mass is suspended from it. Calculate the spring constant in N / m .
rusak2 [61]

Answer:

Spring constant in N / m = 6,000

Explanation:

Given:

Length of spring stretches = 5 cm = 0.05 m

Force = 300 N

Find:

Spring constant in N / m

Computation:

Spring constant in N / m = Force/Distance

Spring constant in N / m = 300 / 0.05

Spring constant in N / m = 6,000

8 0
2 years ago
Perfect symmetrical cone type volcanoes would have what type of drainage pattern
Charra [1.4K]

Perfect symmetrical cone type volcanoes would have radial drainage pattern.

A stratovolcano, also known as a composite volcano, is a conical volcano built up by many layers (strata) of hardened lava, tephra, pumice, and volcanic ash.

If you have any further questions, please don’t hesitate to ask again.

6 0
3 years ago
The​ time, t, required to drive a fixed distance varies inversely as the​ speed, r. It takes 3 hr at a speed of 14 ​km/h to driv
kenny6666 [7]

Answer:

time taken with speed 23 km/h will be 1.8 hours or 1 hour 48 minutes

Explanation:

Given:

Time is inversely proportional to the speed

mathematically,

t ∝ (1/r)

let the proportionality constant be 'k'

thus,

t = k/r

therefore, for case 1

time = 3 hr

speed = 14 km/hr

3 = k/14

also,

for case 2

let the time be = t

r = 23 km/h

thus,

we have

t = k/23

on dividing equation 2 by 1

we get

\frac{t}{3}=\frac{k/23}{k/14}

or

t=\frac{14\times3}{23}

or

t = 1.8 hr = or 1 hour 48 minutes ( 0.8 hours × 60 minutes/hour = 48 minutes)

4 0
3 years ago
The world's largest tires have a mass of 6000 kg
nikitadnepr [17]
Okay!  Thank you for this knowledge
8 0
2 years ago
How much heat is needed to vaporize 10.00 grams of water at 100.0°C? The latent heat of vaporization of water is 2,259 J/g
Nata [24]

Answer:

Heat of vaporization will be 22.59 j    

Explanation:

We have given mass m = 10 gram

And heat of vaporization L = 2.259 J/gram

We have to find the heat required to vaporize 10 gram mass

We know that heat of vaporization is given by Q=mL, here m is mass and L is latent heat of vaporization.

So heat of vaporization Q will be = 10×2.259 = 22.59 J

8 0
2 years ago
Read 2 more answers
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