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r-ruslan [8.4K]

2 years ago

14

A 10 kg block slides on a frictionless surface at 10 m/s . It hits a rough patch 3 meters long with a coefficient of kinetic fri

ction of 0.4. When it reenters the frictionless surface , how fast is it going?

1 answer:

Valentin [98]2 years ago

8 0

12 MPH

I DIDNT do the math my brother did hes in colledge so good lucks guys

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A Cannonball is shot at an angle of 35.0 degrees and is in flight for 11.0 seconds before hitting the ground at the same height

nikdorinn [45]

Answer:

Explanation:

According to Equations of Projectile motion :

$Time\ of\ Flight = \frac{2vsin(x)}{g}$

vsin(x) = 11 * 9.8 / 2 = 53.9 m/sec

(A) v (Initial velocity) = 11 * 9.8 / 2 * sin(35) = 94.56 m/sec

$Maximum Height = \frac{(vsinx)^{2} }{2g}$

(B) Maximum Height = 53.9 * 53.9 / 2 * 9.8 = 142.2 m

$Horizontal Range = vcosx * t$

(C) Horizontal Range = 94.56 * 0.81 * 11 = 842.52 m

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3 years ago

A solid, uniform sphere of mass 2.0 kg and radius 1.7 m rolls without slipping down an inclined plane of height 5.3 m. what is t

inn [45]

<span>Answer: Total kinetic energy at the bottom = 0.5(1+0.4) mv^2 = mgh V^2 = 7*9.8/0.7 V = 9.9m/s Ď‰ = V/r = 9.9/1.7 = 5.8rad/s Answer c. 5.8 rad/s</span>

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3 years ago

What is the deceleration of a bicycle that goes from 40m/s to 20m/s in 5 seconds

Alex Ar [27]

Answer:

$-4 m/s^2$

Explanation:

The acceleration of the bycicle is given by:

$a=\frac{v-u}{t}$

where

v = 20 m/s is the final velocity of the bike

u = 40 m/s is the initial velocity

t = 5 s is the time interval

Substituting numbers, we find

$a=\frac{20 m/s-40 m/s}{5s}=-4 m/s^2$

and the acceleration is negative, which means that the bycicle is slowing down.

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2 years ago