Hi there!
We can use the conservation of angular momentum to solve.

I = moment of inertia (kgm²)
ω = angular velocity (rad/sec)
Recall the following equations for the moment of inertia.

Begin by converting rev/sec to rad sec:

According to the above and the given information, we can write an equation and solve for ωf.

Answer:
Both will reach to same height
Explanation:
Here we can see that friction is to be ignored
so we can say that work done by all the non conservative forces is change in mechanical energy
Since all non conservative forces here is zero
so mechanical energy is conserved here
so here we can say that sum of initial kinetic energy and potential energy = sum of final kinetic energy and potential energy
So we will have

now maximum height is given as

so here we can say that greatest height will be independent of the mass so they both will reach at same height
Answer:
The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false.
Explanation:
The equation for the magnetic force on a charge q moving at velocity v on a magnetic field B is given by the (vectorial) Lorentz Force Law 
From it we can clearly see that the <em>magnitude of the magnetic force </em>exerted on the particle is <em>proportional to the magnitude of the charge q and to the speed v of the particle</em>, and that it is also <em>perpendicular to the particle's velocity</em>. This means that at each instant it moves perpendicularly to the force, so <em>the work done by the magnetic force on the particle is zero</em>.
The statement "if the magnetic force is always perpendicular to the velocity, the path of the particle is a straight line" is false not only for this but for any force, a force always perpendicular to a velocity will curve the trajectory.
I would pick the only one that makes sense, D. optic fibers
Brainliest please
Answer:
The answer is 0.5 Hz
Explanation:
Its pretty easy to get the answer. One hertz (Hz) is equal to one cycle or period per second. So, just divide the period by the number of seconds.
1 period/2 secs = 1/2 Hz or 0.5 Hz