1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naddika [18.5K]
2 years ago
8

Find the radioactivity of a 1 g sample of 226Ra given that

a1" title="t_{1/2}=1620" alt="t_{1/2}=1620" align="absmiddle" class="latex-formula"> years and Avogadro's number = 6.023 × 10^{23}.
Physics
1 answer:
dangina [55]2 years ago
6 0

Answer:

Explanation:

No of atoms of Ra in 1 g of sample = 6.023 x 10²³ / 226

N = 2.66 x 10²¹

disintegration constant λ = .693 / half life

half life = 1620 x 365 x 60 x 60 x 24 = 5.1 x 10¹⁰ s

disintegration constant λ = .693 / 5.1 x 10¹⁰

radioactivity dn / dt = λN

= (.693 / 5.1 x 10¹⁰ )  x 2.66 x 10²¹

= .3614 x 10¹¹ per sec

= 3.614 x 10¹⁰ / s

You might be interested in
Jacques is trying to put a screw into a hard piece of wood, but it is too difficult for him to turn. Which of the following woul
solniwko [45]

Answer:

A. It is the only one that makes sense

Explanation:

3 0
3 years ago
"1.0 kg mass is attached to the end of a spring. The mass has an amplitude of 0.10 m and vibrates 2.0 times per second. Find its
prisoha [69]

Answer:

1.3m/s

Explanation:

Data given,

Mass,m=1.0kg,

Amplitude,A=0.10m,

Frequency,f=2.0Hz.

From the equation of a simple harmonic motion, the displacement of the object at a given time is define as

x=Acos\alpha \\

we can express the velocity by the derivative of the displacement,

Hence

V=-Awsin\alpha \\

at equilibrium, the velocity becomes

V=wA\\w=2\pi f

Hence if we substitute values we arrive at

V=2\pi fA\\V=2\pi *2*0.1\\V=1.3m/s

4 0
3 years ago
Read 2 more answers
What's the diameter of a dish antenna that will receive 10−20W of power from Voyager at this time? Assume that the radio transmi
Murrr4er [49]

Complete Question:

The Voyager 1 spacecraft is now beyond the outer reaches of our solar system, but earthbound scientists still receive data from the spacecraft s 20-W radio transmitter. Voyager is expected to continue transmitting until about 2025, when it will be some 25 billion km from Earth.

What s the diameter of a dish antenna that will receive 10−20W of power from Voyager at this time? Assume that the radio transmitter on Voyager transmits equally in all directions(isotropically).  In fact, the antenna on Voyager focuses the signal in a beam aimed at the earth, so this problem over-estimates the size of the receiving dish needed.

Answer:

d = 2,236 m.

Explanation:

The received power on Earth, can be calculated as the product of the intensity (or power density) times the area that intercepts the power radiated.

As we assume that  the transmitter antenna is ominidirectional, power is spreading out over a sphere with a radius equal to the distance to the source.

So, we can get the power density as follows:

I = P /A = P / 4*π*r², where P = 20 W, and r= 25 billion km = 25*10¹² m.

⇒ I = 20 W / 4*π* (25*10¹²)² m²

The received power, is just the product of this value times the area of the receiver antenna, which we assumed be a circle of diameter d:

Pr = I. Ar =( 20W / 4*π*(25*10¹²)² m²) * π * (d²/4) = 10⁻²⁰ W

Simplifying common terms, we can solve for d:

d= √(16*(25)²*10⁴/20) = 2,236 m.

3 0
3 years ago
A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0 seconds near the surface of a planet. Compared to the a
Whitepunk [10]

Answer:

C) one-half as great

Explanation:

We can calculate the acceleration of gravity in that planet, using the following kinematic equation:

\Delta x=v_0t+\frac{gt^2}{2}

In this case, the sphere starts from rest, so v_0=0. Replacing the given values and solving for g':

g'=\frac{2\Delta x}{t^2}\\g'=\frac{2(22m)}{(3s)^2}\\g'=4.89\frac{m}{s^2}

The acceleration due to gravity near Earth's surface is g=9.8\frac{m}{s^2}. So, the acceleration due to gravity near the surface of the planet is approximately one-half of the acceleration due to gravity near Earth's surface.

5 0
2 years ago
Technician A says that hill assist and hill descent controls are added features to some electronic stability control systems. Te
Pani-rosa [81]

Answer:

Both technicians A and B

Explanation:

Both trailer sway control, hill assist and hill descent controls are additional featires that enhance stability of electronics and their control systems. Majorly, these features track and reduce skidding in electronics, therfore, enhancing electronic system stability. During the process, these newly added features help to automatically apply brakes and direct the sytem where the controller wants to take it.

8 0
2 years ago
Other questions:
  • 5)List an appropriate SI base unit (with a prefix as needed ) for the following:
    13·2 answers
  • A 12.0 v storage battery is connected to three resistors, 6.75 ?, 15.3 ?, and 21.6 ? respectively. the resistors are joined in p
    6·1 answer
  • Two particles having charges of 0.440 nC and 11.0 nC are separated by a distance of 1.80 m . 1) At what point along the line con
    5·1 answer
  • suppose it takes 500 years to form 2 cm of new soil without erosion. Of a farmer need at least 35 cm of soil to plant a particul
    8·1 answer
  • The element oxygen, represented by the symbol O, is classified as
    8·2 answers
  • Ball's velocity be in a year? Assume there are no nearby planets.
    7·1 answer
  • A 25kg ball is thrown into the air. when thrown it is going 10 m/s. calculate how high it travels?
    5·1 answer
  • What is the station's orbital speed? the radius of earth is 6.37×106m, its mass is 5.98×1024kg.
    12·2 answers
  • A bear fells from 10m long grass <br> From where the bear is
    11·1 answer
  • Please help me guys <br>a.<br>b.<br>c.​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!