Answer:
103063860 Pa
Explanation:
= Density of seawater = 1030 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Depth at which pressure is being measured = 10.2 km
The gauge pressure is given by
Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa
(a) the weight of the fish is:
and this is the force that stretches the spring by
. So, we can use Hook's law to find the constant of the spring:
(b) The fish is pulled down by 2.8 cm = 0.028 m more, so now the total stretch of the spring is
But this is also the amplitude of the new oscillation, because this is the maximum extension the spring can get, so A=6.5 cm.
The angular frequency of oscillation is given by:
and so the frequency is given by
A. True
if cold air is replacing warm air it is a cold front and vice versa.